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3 years ago

What is the following product? 3v2(5v6-7v3)

Mathematics

1 answer:

steposvetlana [31]3 years ago

6 0

Answer:

$3v^2\left(5v^6-7v^3\right)=15v^8-21v^5$

Step-by-step explanation:

Given the expression

$3v^2\left(5v^6-7v^3\right)$

Apply the distributive law

$a\left(b-c\right)=ab-ac$

$a=3v^2,\:b=5v^6,\:c=7v^3$

$=3v^2\cdot \:5v^6-3v^2\cdot \:7v^3$

$=3\cdot \:5v^6v^2-3\cdot \:7v^3v^2$

$=15v^8-21v^5$

Thus, we conclude that

$3v^2\left(5v^6-7v^3\right)=15v^8-21v^5$

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Factor the trinomial:<br> 3x2 + 13x + 12

yarga [219]

Answer:

Step-by-step explanation:

(3x + 4)(x + 3)

3x^2 + 9x + 4x + 12

3x^2 + 13x + 12

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3 years ago

Find the vertical asymptotes. 2x2 + 7x + 6 y = 3x2 + 10x - 8 * = [ [?], x=

Llana [10]

Answer:

$-\frac{77}{24}$

Step-by-step explanation:

1. rewrite the equation in standard form: $4\cdot \frac{3}{2}\left(y-\left(-\frac{41}{24}\right)\right)=\left(x-\left(-\frac{3}{2}\right)\right)^2$

2. find (h,k), the vertex. the vertex is $\left(h,\:k\right)=\left(-\frac{3}{2},\:-\frac{41}{24}\right)$

3. find the 'focal length' of the parabola - the focal length is the distance between the vertex and the focus. from the vertex we can see that the focal length, p, = 3/2

4. Parabola is symmetric around the y-axis and so the asymptote is a line parallel to the x-axis, a distance p from the $\left(-\frac{3}{2},\:-\frac{41}{24}\right)$ y coordinate which is at $-\frac{41}{24}\right)$ . Set up the equation:

$y=-\frac{41}{24}-p$

5. substitute and solve:

$y=-\frac{41}{24}-\frac{3}{2}$

$y = -\frac{77}{24}$

hope this helps, ask me questions if you still don't understand.

8 0

3 years ago

Answer <br> If 1+4=5 and 2+5=12 and 3+6=21 how much does 5+8=

Anna11 [10]

The answer would be 34. The pattern looks like they are adding the sum to the next expression. So 21+5+8=34. Hope I could help!!:-)))

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3 years ago

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KengaRu [80]

Answer:

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3 years ago

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Eduardwww [97]

Answer:

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Step-by-step explanation:

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3 years ago