If a bird is on the ground, 7 ft away from a 10 ft tall tree, then what is the angle (to the
1 answer:
Answer:
The angle is 55°
Step-by-step explanation:
To find the angle at which a bid is looking up on top of a tree that is 10feet tall if the bird is on the ground 7 feet away from the tree, we will follow the steps below:
we will use trigonometric ratio to find the angle
SOH CAH TOA
sinФ = opposite / hypotenuse
cosФ = adjacent / hypotenuse
tanФ = opposite /adjacent
from the diagram below, opposite = 10 feet and adjacent = 7 feet
the best trig.ratio to use is tan
tanФ = opposite /adjacent
tanФ = 10 /7
tan Ф =1.42857
to get the value of Ф, we will take the tan⁻¹ of both-side
tan⁻¹ tan Ф = tan⁻¹ 1.42857
Ф= tan⁻¹ 1.42857
Ф≈55°
Therefore, the angle is 55°
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Answer:
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Step-by-step explanation:
<u>Given system:</u>
- y ≥ 2x + 1
- y ≤ 2x – 2
The solution is the common area shaded by the inequalities.
The lines are parallel because of same slope.
Both lines are solid because of equal sign in both inequalities.
The first inequality has a y-intercept of 1 and shaded area is to the left of the line since the value of y is greater as x increases.
The second inequality has a y-intercept of -2 and shaded area is to the right of the line since the value of y is greater as x increases.
The matching graph is the second picture (or attached below) and there is no solution.
Speed of the east bound cyclist is 12 mph and the speed of west bound cyclist is 15 mph.
<u>Solution:</u>
Let us assume that x is speed of slower eastbound cyclist
So, x+3 will be the speed of faster westbound cyclist
We know that distance is the product of speed and time. That is,
West-bound DATA:
Rate of speed = x+3 mph ; Time = 6 hrs ; distance = 6(x+3) = 6x+18 miles
East-bound DATA:
Rate of speed = x mph ; time = 6 hrs. ; distance = 6x miles
On solving,
Distance apart = 162
So, the rate of speed of the east bound cyclist is 12 mph and the rate of speed of the west bound cyclist will be
Answer:
12.
Step-by-step explanation:
Substitute this equation with a=3 and b=24: