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3 years ago

What is the result of adding

Mathematics

2 answers:

Vika [28.1K]3 years ago

8 0

It builds up to an answer

Aliun [14]3 years ago

6 0

Answer: You get an answer?

Step-by-step explanation:

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Anna bought a potted plant online. It cost $3.4 5plus 20% shipping and handling.What was the total cost

eimsori [14]

Answer:

Total cost = $4.08

Step-by-step explanation:

Given the following data;

Selling price = $3.4

Shipping and handling fee = 20%

To find the total cost;

First of all, we would determine the extra fee;

Extra fee = 20/100 * 3.4

Extra fee = 68/100

Extra fee = $0.68

Now, we can solve for the total cost using the formula below;

Total cost = selling price + extra fee

Total cost = 3.4 + 0.68

Total cost = $4.08

5 0

3 years ago

Find x if x-8=2(x+4)

Fofino [41]

Answer:

$x=-16$

Step-by-step explanation:

$x-8=2(x+4)\\x-8=2x+8\\-x=16\\x=-16$

4 0

3 years ago

Read 2 more answers

Evaluate the expression of a=9 and b=3 a+b+a divided by b

astra-53 [7]

Answer:

hope it's helpful ❤❤❤❤❤❤

THANK YOU.

7 0

3 years ago

Read 2 more answers

Which of the following is a solution to the equation x + 16 = -14?

IRINA_888 [86]

Answer:

x = -30

Step-by-step explanation:

Step 1: Subtract 16 from both sides

x + 16 = -14

x + 16 - 16 = -14 - 16

x = -30

Answer: x = -30

7 0

4 years ago

Read 2 more answers

1. What is the solution to the system of equations?

boyakko [2]

Answer:

$\large\boxed{x=-8\ and\ y=9\to(-8,\ 9)}$

Step-by-step explanation:

$a)\ \text{Elimination method:}\\\\\left\{\begin{array}{ccc}3x+4y=12\\x+2y=10&\text{multiply both sides by (-2)}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}3x+4y=12\\-2x-4y=-20\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad \boxed{x=-8}\\\\\text{Put the value of x to the second equation:}\\-8+2y=10\qquad\text{add 8 to both sides}\\2y=18\qquad\text{divide both sides by 2}\\\boxed{y=9}$

$b)\ \text{Substitution method:}\\\\\left\{\begin{array}{ccc}3x+4y=12\\x+2y=10&\text{subtract 2y from both sides}\end{array}\right\\\\\left\{\begin{array}{ccc}3x+4y=12&(1)\\x=10-2y&(2)\end{array}\right\qquad\text{subtract (2) to (1)}\\\\3(10-2y)+4y=12\qquad\text{use distributive property}\\(3)(10)+(3)(-2y)+4y=12\\30-6y+4y=12\qquad\text{subtract 30 from both sides}\\-2y=-18\qquad\text{divide both sides by (-2)}\\\boxed{y=9}\\\\\text{Put the value of y to (2):}\\x=10-2(9)\\x=10-18\\\boxed{x=-8}$

5 0

3 years ago