Answer:
B = 4
T = 2
Step-by-step explanation:
First, figure out the equation.
We know that bicycles have 2 wheels, that there are 3 on a tricycle, and there are a total of 14 wheels and a total of 6 bicycles and tricycles.
Let b stand for bicycles and t stand for tricycles:
14 = 2b + 3t
6 = b + t
We can figure out the amount of either by rearranging the second equation to isolate one variable. I will solve it in two ways
In the first way, I will solve for b
(-t) 6 = b + t (-t)
6 - t = b
Plug this into the first equation and solve for remaining variable
14 = 2(6 - t) +3t
14 = 12 - 2t + 3t
14 = 12 +t
-12 -12
2 = t
6 - 2 = b
b = 4
The second way was to solve for t first
(-b) 6 = b + t (-b)
6 - b = t
14 = 2b + 3(6 - b)
14 = 2b + 18 - 3b
(-18) 14 = 18 -b (-18)
-4/-1 = -b/-1
b = 4
6 - 4 = t
t = 2
It doesn't matter which way you go, they both give you the exact same answer.
Sooo, recap!
1) write equations
2) switch the easier of the two to isolate one variable
3) substitute to find other variable (x2)
4) Find answers! =D
Hope this helps!
In an arithmetic sequence, the difference between consecutive terms is constant. In formulas, there exists a number such that
In an geometric sequence, the ratio between consecutive terms is constant. In formulas, there exists a number such that
So, there exists infinite sequences that are not arithmetic nor geometric. Simply choose a sequence where neither the difference nor the ratio between consecutive terms is constant.
For example, any sequence starting with
Won't be arithmetic nor geometric. It's not arithmetic (no matter how you continue it, indefinitely), because the difference between the first two numbers is 14, and between the second and the third is -18, and thus it's not constant. It's not geometric either, because the ratio between the first two numbers is 15, and between the second and the third is -1/5, and thus it's not constant.
Answer:
60,000
Step-by-step explanation:
Jane-2000
Peter-ratio of 5=25000
Marta-ratio of 7=35000
25000+35000
60000
3x+1=1 because it is a hard problem to solve just ask your teacher