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3 years ago

What’s the correct answer for this?

Mathematics

1 answer:

makkiz [27]3 years ago

8 0

Answer:

PO = 36

Step-by-step explanation:

Since both the chords are equal in length so they must be equidistant from the centre.

And

PG = GO

-x+10 = -3(x+2)

-x+10 = -3x-6

-x+3x = -6-10

2x = -16

Dividing both sides by 2

x = -8

Now

PO = PG + GO

PO = -(-8)+10+(-3)((-8)+2)

PO = 8+10+(-3)(-6)

PO = 18+18

PO = 36

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Solve for z: yz + 4z = z - y²<br><br><br><br>

poizon [28]

Answer:

Step-by-step explanation:

yz+4z=z-y²

yz+4z-z=-y²

yz+3z=-y²

z(y+3)=-y²

$z=-\frac{y^2}{y+3 }$

3 0

2 years ago

In triangle abc, the measure of angle b is 20 more than three times the measure of angle

sleet_krkn [62]

Let x be the degree of angle a.

Angle b: 20+3x
Angle c: 55+x

We know that all angles add up to 180 degrees.

180=x+(20+3x)+(55+x)
180= 5x+75
180-75=5x
105/5=x
21=x

Angle a: 21 degrees
Angle b: 20+3(21) => 83 degrees
Angle c: 21+55 => 76 degrees

Hope I helped :)

5 0

3 years ago

If we sample from a small finite population without replacement, the binomial distribution should not be used because the event

seropon [69]

Answer:

5/4324 = 0.001156337

Step-by-step explanation:

To better understand the hyper-geometric distribution consider the following example:

There are 100 senators in the US Congress, and suppose 60 of them are republicans so 100 - 60 = 40 are democrats).

We extract a random sample of 30 senators and we want to answer this question:

What is the probability that 10 senators in the sample are republicans (and of course, 30 - 10 = 20 democrats)?

The answer using the h-g distribution is:

$\large \frac{\binom{60}{10}\binom{100-60}{30-10}}{\binom{100}{30}}=\frac{\binom{60}{10}\binom{40}{20}}{\binom{100}{30}}$

Now, imagine there are 56 senators (56 lottery numbers), 6 are republicans (6 winning numbers and 50 losers), we extract a sample of 6 senators (the bettor selects 6 numbers). What is the probability that 4 senators are republicans? (What is the probability that 4 numbers are winners?).

<em>As we see, the situation is exactly the same,</em> but changing the numbers. So the answer would be

$\large \frac{\binom{6}{4}\binom{56-6}{6-4}}{\binom{56}{6}}=\frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}$

Now compute each combination separately:

$\large \binom{6}{4}=\frac{6!}{4!2!}=15\\\\\binom{50}{2}=\frac{50!}{2!48!}=1225\\\\\binom{50}{6}=\frac{50!}{6!44!}=15890700$

and now replace the values:

$\large \frac{\binom{6}{4}\binom{50}{2}}{\binom{56}{6}}=\frac{15*1225}{15890700}=\frac{18375}{15890700}=\frac{5}{4324}$

and that is it.

If the decimal expression is preferred then divide the fractions to get 0.001156337

6 0

3 years ago

Dingane has \$8.00$8.00dollar sign, 8, point, 00, and exactly 30\%30%30, percent of that money is from 555‑cent coins. How many

Ipatiy [6.2K]

<span>If Dingane has $8.00, and thirty percent of that money is from five cent coins, then 8 x 0.3 = $2.40 of Dingane's money is made of five cent coins. In this case the number of five cent coins is the number of cents divided by five: 240/5 = 48. Therefore, Dingane has forty-eight five-cent coins.</span>

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3 years ago

An office supply company sells two types of fax

Phantasy [73]

14 of the machine that cost $150 was sold and 8 of the machine that cost $225 was sold.

To solve this problem, we would write a system of linear equations.