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zlopas [31]
4 years ago
9

What is the solution to this equation? X/2-7=15

Mathematics
1 answer:
Contact [7]4 years ago
7 0

Answer:

<h2>x = 44</h2>

Step-by-step explanation:

\dfrac{x}{2}-7=15\qquad\text{add 7 to both sides}\\\\\dfrac{x}{2}-7+7=15+7\\\\\dfrac{x}{2}=22\qquad\text{multiply both sides by 2}\\\\x=44

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The area of the rectangle shown is 2x^2-x-15 square units. What is the width of the rectangle?
yuradex [85]

Answer:

<h2>The width is (2x + 5) or (x - 3)</h2>

Step-by-step explanation:

The formula of an area of a rectangle:

A=lw

l - length

w - width

We have

A=2x^2-x-15

2x^2-x-15=2x^2+5x-6x-15=x(2x+5)-3(2x+5)\\\\=(2x+5)(x-3)

3 0
4 years ago
Which define a right triangle?
BartSMP [9]

Answer:

no

yes

no

Step-by-step explanation:

---------------------

8 0
3 years ago
A marathon runner travels 7/4 of a mile in 1/4 hour. What is the runner's unit rate?
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3 0
3 years ago
Read 2 more answers
Area of circle with diameter of 1 m?
Elena-2011 [213]

Answer:

A = 0.785m²

B = 31400cm²

C = 7850cm²

D = 785,000mm²

Step-by-step explanation:

To solve this question, we'll have to find the area of a circle which is

Area of a circle = πr²

1. The diameter of the circle = 1m

Area of a circle = πr²

r = radius of the circle

π = 3.14

Radius = diameter / 2

Radius = 1 / 2 = 0.5m

Area = 3.14 × (0.5)²

Area = 3.14 × 0.25

Area = 0.785m²

2. Radius = 100cm

Area of a circle = πr²

Area = 3.14 × (100)²

Area = 3.14 × 10000

Area = 31400cm²

3. Diameter = 100cm

Area = πr²

Radius = diameter / 2

Radius = 100 / 2

Radius = 50cm

Area = πr²

Area = 3.14 × (50)²

Area = 3.14 × 2500

Area = 7850cm²

4. Radius = 500mm

Area = πr²

Area = 3.14 × (500)²

Area = 3.14 × 250,000

Area = 785,000mm²

7 0
4 years ago
Read 2 more answers
Kyra is using rectangular tiles of two types for a floor design. They Tyler each type is shown below:​
sattari [20]

Answer:  b) the tiles are not similar because both SP:SR is 5:4 and MJ:ML is 5:2

<u>Step-by-step explanation:</u>

We are given that the tiles are rectangular which implies that they both have a 90° angle.

In order to prove similarity, We need to show that the lengths and widths are proportional.

P Q R S

J  K L M

a) PQ : QR         JK : LM

  w=4  L=5        w=2 w=2

                                  ↓

                                 We need Length (not width)

b) SP : SR         MJ : ML

  L=5  w=4        L=5 w=2

      5 : 4               5 : 2

When comparing length to width they do not have the same ratio so the rectangles are not similar.

c) PQ : QR         JK : KL

  w=4  L=5        w=2 L=5

      4 : 5               2 : 5

When comparing width to length they do not have the same ratio so the rectangles are not similar.

d) SR : ML         PQ : JK

  w=4  w=2        w=4 w=2

           ↓                     ↓

  We need Length (not width)

                       

                             

6 0
4 years ago
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