-29 is 29 bars away from 0. 100 is 100 bars away from 0.
29 + 100 = 129
So the distance between -29 and 100 is 129. The answer is D.
21345+12345=33690
33690-326=33364
The answer is 33364.
What this question is asking us is
A) From -40C to 5 0c How much did it rise
The formula for this would be
Risen Temperature - Initial Temperature
The risen temparauture is 5 so we plug the 5 in first then the 4 so it would look like
5-(-4)=9
And remeber when you have 2 negatives it becomes a positie, 5+4=9
The asnwer for A is 9 degress
B) The tempurater then fell by 7 degress from 5 so we just have to do
5 - 7
which is -2 Celcius
Answer:
Step-by-step explanation:
(-4,2) belongs in this direct variation.
Step-by-step explanation:
Let the direct variation relationship is expressed by the equation y = mx ........ (1), where x and y are in direct variation and k is the variation constant.
Now, the point (4,-2) is included in the direct variation relationship, then from equation (1) we get, -2 = 4m
⇒
Therefore, the equation (1) becomes
⇒ x + 2y = 0 ......... (2)
Now, from the given four options only the point (-4,2) satisfies the
The force of friction is given in the scenario:
Force = 500 Newton
and the mass of the runner is 60 kg
To find the acceleration we need to use the relation between force, mass, and the acceleration of the object:
Where 'F' represents the force, 'm' represents the mass, and 'a' represents the acceleration.
Plugging the value of variables we get:
Solving for 'a' (acceleration) we get:
Newton/kilogram or meters/ second squared
So the acceleration of the runner is 8.33 meters/ second squared.
