9514 1404 393
Answer:
2
Step-by-step explanation:
I find it convenient to remember that a logarithm is an exponent.
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log₂(8) +log₃(1/3) = log₂(2³) +log₃(3⁻¹)
= 3 -1 = 2
The value of the expression is 2.
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Some calculators can compute this for you directly.
we know that
<u>in the triangle PQR</u>
m∠PQR+m∠QPR+m∠QRP=180°------> the sum of the internal angles of a triangle is equal to 180 degrees
(m∠PQR+m∠QRP)+74°=180°-------> (m∠PQR+m∠QRP)=106°
we know that
If QS and SR are angle bisectors
then
<u>In the triangle QSR</u>
m∠SQR+m∠QSR+m∠QRS=180°-------> equation 1
and
(m∠SQR+m∠QRS)=106°/2--------> (m∠SQR+m∠QRS)=53°
substitute the value of (m∠SQR+m∠QRS)=53° in the equation 1
53°+m∠QSR=180°
m∠QSR=180°-53°-------->m∠QSR= 27°
therefore
<u>the answer is</u>
The measure of angle QSR is 27 degrees
Answer:
x = 6.2608
Step-by-step explanation:
23x=144
Answer:
(-4, 2)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
-6x + 5y = 34
-6x - 10y = 4
<u>Step 2: Rewrite Systems</u>
-6x + 5y = 34
- Multiply everything by -1: 6x - 5y = -34
<u>Step 3: Redefine Systems</u>
6x - 5y = -34
-6x - 10y = 4
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Elimination</em>
- Combine 2 equations: -15y = -30
- Divide -15 on both sides: y = 2
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define equation: -6x - 10y = 4
- Substitute in <em>y</em>: -6x - 10(2) = 4
- Multiply: -6x - 20 = 4
- Add 20 on both sides: -6x = 24
- Divide -6 on both sides: x = -4
Answer:
y=-9
x=10
Step-by-step explanation:
happy to help and if needed the step just ask and i'll explain it
