The correlation coefficient is -0.87; strong correlation
<h3>How to determine the correlation coefficient?</h3>
The given parameters are:
x = Time spent working out
y = lbs Overweight
Next, we enter the table of values in a graphing tool.
From the graphing tool, we have the following summary:
<u>X Values</u>
- ∑ = 27.1
- Mean = 2.71
- ∑(X - Mx)2 = SSx = 22.569
<u>Y Values</u>
- ∑ = 89
- Mean = 8.9
- ∑(Y - My)2 = SSy = 778.9
<u>X and Y Combined</u>
- N = 10
- ∑(X - Mx)(Y - My) = -114.19
<u>R Calculation</u>
r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))
r = -114.19 / √((22.569)(778.9))
r = -0.8613
Approximate
r = -0.87
This means that the correlation coefficient is -0.87
Also, the correlation coefficient is a strong correlation, because it is closer to -1 than it is to 0
Read more about correlation coefficient at:
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-2.75 is less then -2.5 or -2.50. For negatives only, if the number is less it is greater, and if a number is greater it is less.
Brainliest please!
We can solve this problem by referring to the standard
probability distribution tables for z.
We are required to find for the number of samples given the
proportion (P = 5% = 0.05) and confidence level of 95%. This would give a value
of z equivalent to:
z = 1.96
Since the problem states that it should be within the true
proportion then p = 0.5
Now we can find for the sample size using the formula:
n = (z^2) p q /E^2
where,
<span> p = 0.5</span>
q = 1 – p = 0.5
E = estimate of 5% = 0.05
Substituting:
n = (1.96^2) 0.5 * 0.5 / 0.05^2
n = 384.16
<span>Around 385students are required.</span>
0.625 which is approximately equal to 0.63 is 5/8 in decimal form.
