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prohojiy [21]
3 years ago
15

Sarah kept track of the points she scored during her first five basketball games in the table shown.

Mathematics
1 answer:
grandymaker [24]3 years ago
4 0

Answer:

E

Step-by-step explanation:

If you add 22 onto the sum of all the points and divide by the amount of games (6), you get 12.

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PLEASE ANSWER SOON<br> Has a picture of question
earnstyle [38]
The answer is 21 which comes from 7 * 3.

Draw the four points in a complex plane. From the drawing you can see that the lenght is 4i - (-3i) = 4i + 3i = 7i, and the width is 1 - (-2) = 1 + 2 = 3.

So, the area is 7 * 3 = 21.




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3 years ago
Sarah and her friends pick 3 3/4 pints of blueberries after they ate some of the blueberries only 2 1/3 pints remain how many pi
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3 3/4  - 2 1/3

get a common denominator of 12

3 3/4 * 3/3 = 3 9/12

2 1/3 * 4/4 = 2 4/12

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1 5/12

Answer: they ate 1 5/12 pints

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3 years ago
The hypotenuse of a right triangle is 7 inches,and one of the legs is 13 inches.Find the length of the other leg.
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6 0
4 years ago
Select all the correct answers.
Fofino [41]

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6 0
3 years ago
Choose 5 cards from a full deck of 52 cards with 13values (2, 3, 4, 5, 6, 7, 8, 9, 10, J, Q, K, A) and 4 kinds(spade, diamond, h
Delvig [45]

Answer:

a) 182 possible ways.

b) 5148 possible ways.

c) 1378 possible ways.

d) 2899 possible ways.

Step-by-step explanation:

The order in which the cards are chosen is not important, which means that we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question, we have that:

There are 52 total cards, of which:

13 are spades.

13 are diamonds.

13 are hearts.

13 are clubs.

(a)Two-pairs: Two pairs plus another card of a different value, for example:

2 pairs of 2 from sets os 13.

1 other card, from a set of 26(whichever two cards were not chosen above). So

T = 2C_{13,2} + C_{26,1} = 2*\frac{13!}{2!11!} + \frac{26!}{1!25!} = 182

So 182 possible ways.

(b)Flush: five cards of the same suit but different values, for example:

4 combinations of 5 from a set of 13(can be all spades, all diamonds, and hearts or all clubs). So

T = 4*C_{13,5} = 4*\frac{13!}{5!8!} = 5148

So 5148 possible ways.

(c)Full house: A three of a kind and a pair, for example:

4 combinations of 3 from a set of 13(three of a kind ,c an be all possible kinds).

3 combinations of 2 from a set of 13(the pair, cant be the kind chosen for the trio, so 3 combinations). So

T = 4*C_{13,3} + 3*C_{13.2} = 4*\frac{13!}{3!10!} + 3*\frac{13!}{2!11!} = 1378

So 1378 possible ways.

(d)Four of a kind: Four cards of the same value, for example:

4 combinations of 4 from a set of 13(four of a kind, can be all spades, all diamonds, and hearts or all clubs).

1 from the remaining 39(do not involve the kind chosen above). So

T = 4*C_{13,4} + C_{39,1} = 4*\frac{13!}{4!9!} + \frac{39!}{1!38!} = 2899

So 2899 possible ways.

4 0
3 years ago
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