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Sholpan [36]
2 years ago
6

3X +17+ 5X equals 7X +10

Mathematics
2 answers:
Illusion [34]2 years ago
5 0
The answer is x=-7
you minus 7x to the left side and minus 17 to the right side then you get x= 10-17 which is x=-7
iren [92.7K]2 years ago
4 0

Answer:

I think the answer is x= -7.

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Pls help me with this question
g100num [7]

Answer:

its 6

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Please help, question in pic
Ray Of Light [21]

Answer:

D

Step-by-step explanation:

hard to explain but when you rotate 180, you can imagine that a straight line with the center of rotation as the midpoint can be drawn between the image and preimage. you want a mapped to c and you want d mapped to b. having it rotate 180 with the center of rotation being the center of the parallelogram allows you to make those imaginary lines between a and c and d and b. hope this helps

3 0
2 years ago
6.A = 23 × 3 × 5 B = 22 × 3 × 52
frez [133]

Given:

The two numbers are

A=23\times 3\times 5

B=22\times 3\times 52

To find:

The highest common factor (HCF) of A and B

Solution:

We have,

A=23\times 3\times 5               ...(i)

B=22\times 3\times 52

All the factors of A are prime but the factors of B are not prime. So, it can be written as

B=2\times 11\times 3\times 13\times 2\times 2          ...(ii)

From (i) and (ii), it is clear that 3 is the only common factor of A and B. So,

HCF(A,B) = 3

Therefore, the highest common factor (HCF) of A and B is 3.

6 0
3 years ago
What is the first quartile of the data set: {13, 15, 19, 35, 25}
Gekata [30.6K]

Answer:

first quartile is 14

Step-by-step explanation:

{13,15,19,25,35}

first quartile = (13+15)/2 = 14

second quartile = 19

third quartile = (25+35)/2 = 30

3 0
3 years ago
Read 2 more answers
20 Points! Please Help!
ivolga24 [154]

To solve this problem yo need to have the "x", the "y", and the radius. To find the radius since it is not given we use the formula.

sq rt(-3^2+1^2)

sq rt(9+1)

sq rt(10) would be the length of the radius in this case.

Then we use the sine cosine and tangent fractions

sin:y/r

cos:x/r

tan:y/x

With the values plugged in the equations are

SIN:1/sqrt(10) Since there can´t be a sq rt in hte denominator we change it to 1(sq rt(10))/10

COS:-3/sqrt(10) Since there can´t be a sq rt in the denominator we change it to -3(sq rt(10))/10

TAN:1/-3 This one can stay the same.

This would be the measures of SIN, COS, and TAN.

3 0
3 years ago
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