Solve. −x2 = 2x − 15
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Given:
A line through the points (7,1,-5) and (3,4,-2).
To find:
The parametric equations of the line.
Solution:
Direction vector for the points (7,1,-5) and (3,4,-2) is
Now, the perimetric equations for initial point with direction vector
, are
The initial point is (7,1,-5) and direction vector is . So the perimetric equations are
Similarly,
Therefore, the required perimetric equations are and
.