Answer:
<em>0m</em>
Step-by-step explanation:
Before the ball is thrown, it is at the ground level. At the ground level, the height is zero. Substitute h = 0 into the equation;
h(x)=-x^2+10x-16
0=-x^2+10x-16
x^2-10x+16 = 0
Factorize
x^2-8x-2x+16 = 0
x(x-8) - 2 (x-8) = 0
x-2 = 0 and x - 8 = 0
x = 2 and 8
At x = 2
h(2) = -2^2 + 10(2) - 16
h(2) = -4 + 4
h(2) = 0
<em>Hence the height of the ball at the time it is thrown is 0m</em>
Answer:
1) 6*5-4
2) 17 - (5+9)
Step-by-step explanation:
The 4th number is 10, since you need to add 10 to get 32 so that when you divide by 4 you get 8
So we know 5ft to 1cm then
4x5=20ft
6x5=30ft
Answer: 
Step-by-step explanation:
The exponent 1/3 is the same thing as cube rooting the expression.
![\sqrt[3]{27\sqrt[3]{z^2} }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%5Csqrt%5B3%5D%7Bz%5E2%7D%20%7D)
3*
Hope it helps <3
