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prohojiy [21]
3 years ago
5

The local supermarket is selling melons at the price of 2 for 3.00. At this rate, what is the price for 5 melons?

Mathematics
1 answer:
svp [43]3 years ago
8 0
2 melons for $3 
4 melons = $6 
1 melon is half of $3 = $1.50 
4 melons = $6 + $1.50 = $7.50 for 5 melons 
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Can someone help me with section b please and thank you ​
blondinia [14]
Y=3x
It costs $3 per movie (x)
8 0
3 years ago
Aanand earns Rs 80 in 7 hours and pramode earns Rs 90 in 12 hours. find their ratio​
My name is Ann [436]

Answer:

1.671:1

Step-by-step explanation:

80/7=11.99(9) or ~12

90/12= 7.177(7)

11.99(9)/7.177(7)=1.671

1.671:1

6 0
3 years ago
Sonya made a graph showing the first ten minutes of her drive to the movies.
Agata [3.3K]

Answer:

A

Step-by-step explanation:

A. because the first point shows her acceleration and you can see her speed increasing when she hits the second point, so we can say that see accelerated up the ramp and after it hits the third point her speed becomes constant all the way when she reached the highway

4 0
3 years ago
Read 2 more answers
Perpendicular to y=4x-7; contains the point (4,3)
san4es73 [151]
Okay, so a general rule for finding perpendicular lines in the form of y = mx + b is y = (-1/m) + b.
First, let's ignore b (-7) because we're going to find that later.
A perpendicular line to y = 4x + b is y = -1/4x + b.
Alright, so now let's plug in the values. They are in the form of (x,y), so let's plug them in accordingly.

3 = -1/4(4) + b
3 = -1 + b
b = 4
y = -1/4x + 4
So a line perpendicular to y = 4x - 7 is y = -1/4x + 4.
5 0
3 years ago
The growth of a city is described by the population functionwhereis the initial population of the city, t is the time in years,
mamaluj [8]

Complete question:

The growth of a city is described by the population function p(t) = P0e^kt where P0 is the initial population of the city, t is the time in years, and k is a constant. If the population of the city atis 19,000 and the population of the city atis 23,000, which is the nearest approximation to the population of the city at

Answer:

27,800

Step-by-step explanation:

We need to obtain the initial population(P0) and constant value (k)

Population function : p(t) = P0e^kt

At t = 0, population = 19,000

19,000 = P0e^(k*0)

19,000 = P0 * e^0

19000 = P0 * 1

19000 = P0

Hence, initial population = 19,000

At t = 3; population = 23,000

23,000 = 19000e^(k*3)

23000 = 19000 * e^3k

e^3k = 23000/ 19000

e^3k = 1.2105263

Take the ln

3k = ln(1.2105263)

k = 0.1910552 / 3

k = 0.0636850

At t = 6

p(t) = P0e^kt

p(6) = 19000 * e^(0.0636850 * 6)

P(6) = 19000 * e^0.3821104

P(6) = 19000 * 1.4653739

P(6) = 27842.104

27,800 ( nearest whole number)

3 0
3 years ago
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