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3 years ago

5

Help plz help plz help plz help plz

2 answers:

NARA [144]3 years ago

8 0

Answer:

Step-by-step explanation:

21. 136° and b are supplementary, meaning they have a sum of 180°. This means that 136° + b = 180° → b = 44°.

22. Again, the angles are supplementary which means that 61° + b = 180° → b = 119°.

23. Again, they are supplementary which means that x - 22° + 135° = 180° → x + 113° = 180° → x = 67°.

24. I'm pretty sure you get the gist of this. 6x + 3° + 87° = 180° → 6x + 90° = 180° → 6x = 90° → x = 15°

Hope this helps!

kow [346]3 years ago

7 0

Answer:

139o

Step-by-step explanation:

You might be interested in

Find the complex fourth roots \[-\sqrt{3}+\iota \] in polar form.

____ [38]

Let $z=-\sqrt3+i$ . Then

$|z|=\sqrt{(-\sqrt3)^2+1^2}=2$

$z$ lies in the second quadrant, so

$\arg z=\pi+\tan^{-1}\left(-\dfrac1{\sqrt3}\right)=\dfrac{5\pi}6$

So we have

$z=2e^{i5\pi/6}$

and the fourth roots of $z$ are

$2^{1/4}e^{i(5\pi/6+k\pi)/4}$

where $k\in\{0,1,2,3\}$ . In particular, they are

$2^{1/4}e^{i(5\pi/6)/4}=2^{1/4}e^{i5\pi/24}$

$2^{1/4}e^{i(5\pi/6+2\pi)/4}=2^{1/4}e^{i17\pi/24}$

$2^{1/4}e^{i(5\pi/6+4\pi)/4}=2^{1/4}e^{i29\pi/24}$

$2^{1/4}e^{i(5\pi/6+6\pi)/4}=2^{1/4}e^{i41\pi/24}$

7 0

3 years ago

Two angles are supplementary one angle measure 12 more than the other find the measures

Furkat [3]

We have a + b = 180 and a = 12 + b;
Then, 12 + b + b = 180;
12 + 2b = 180;
2b = 168;
b = 84;
a = 12 + 84;
a = 96;

5 0

3 years ago

(a) Suppose Y1(t) is a solution of an autonomous system dY/dt = F(Y). Show that Y2(t) = Y1(t +t0) is also a solution for any con

alexandr1967 [171]

Answer:

Step-by-step explanation: see attachment

6 0

3 years ago

Drag numbers to use a negative factor to factor the expression –5g + 15h – 25. Numbers may be used once, more than once, or not

Gala2k [10]

Answer:

(5g –15h +25)

hope dis helps ^-^

6 0

3 years ago

Find the seventh term of the

jekas [21]

Answer:

$T_7 = \frac{64}{729}$

Step-by-step explanation:

Given

$a =1$

$r = \frac{2}{3}$

Required

Determine the 7th term

The nth term of a gp is:

$T_n = a * r^{n-1$

So, we have:

$T_7 = 1 * \frac{2}{3}^{7-1$

$T_7 = 1 * \frac{2}{3}^{6$

$T_7 = 1 * \frac{2^6}{3^6}$

$T_7 = 1 * \frac{64}{729}$

$T_7 = \frac{64}{729}$

6 0

3 years ago