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2 years ago

Which is equivalent to -4 sqrt of 9 1/2x

1 answer:

3 0

To solve this problem you can apply the proccedure shown below:
1. You have the fexpression given in the problem above, which you can rewrite it as following:
-4√(9/2x)
2. You can find an equivalent expression:
-4√(3²/2x)
(-4)(3)√(1/2x)
-12/√2x
3- If you multiply the numerator and the denominator by √2, you obtain:
(-12√2)/[(√2)²√x]
(-12√2)/(2√x)
(-6√2)/(√x)
Therefore, the answer is:-(-6√2)/(√x)

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Zuri is stuck in traffic. She notices that she only drove 3 miles in 15 minutes.

makkiz [27]

Answer:

0.2

Step-by-step explanation:

3/15=0.2

6 0

2 years ago

Which parabola has the graph shown?<br><br> I think the answer is C. however, I'm not 100% sure.

NemiM [27]

$x=m(y-k)^2+h\\\\(h,\ k)-the\ vertex$

We have the vertex (-4, -1), therefore we have:

$x=(y-(-1))^2-4\ \ \ |+4\\\\(x+4)=(y+1)^2$

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3 years ago

For the following right triangle, find the side length x. Round your answer to the nearest hundredth.

Pani-rosa [81]

Answer:

x = 14.25

Step-by-step explanation:

Start with a^2 + b^2 = c^2

a = 11

b = x

c = 18

plug in and solve

11^2 + x^2 = 18^2

121 + x^2 = 324 - Simplify

x^2 = 203 - subtract 121 from both sides

x = 14.247 rounds to 14.25 - square root on both sides

7 0

2 years ago

Hello I need help Finding the probability

Stolb23 [73]

Each petal of the region $R$ is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length $5\sqrt2$ , which implies the segment is subtended by an angle of $\dfrac\pi2$ . This means the area of the segment is

$\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}$
$\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2$

This means the area of one petal is $\dfrac{25\pi}2-25$ , and the area of $R$ is four times this, or $50\pi-100$ .

Meanwhile, the area of $G$ is simply the area of the square minus the area of $R$ , or $10^2-(50\pi-100)=200-50\pi$ .

So

$\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1$
$\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2$
$\mathbb P((X=R)\land(X=G))=0$ (provided these regions are indeed disjoint; it's hard to tell from the picture)
$\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1$

4 0

3 years ago

Find the inverse of the rational function f(x)=2x/x+3

SashulF [63]

Answer:

${f(x)}^{ - 1} = \frac { - 3x}{x - 2}$

Step-by-step explanation:

check image above

sorry for my handwriting

5 0

2 years ago