A(n)=4+4(n-1)
a(n)=4+4n-4
a(n)=4n
76=4n
n=19
The sum of any arithmetic sequence (series are infinite) is:
(a+a(n))(n/2)
The average of the first and last terms times the number of terms, in this case we found that n=19 so:
19(4+76)/2=760
Answer:
cosA ≈ 0.55
Step-by-step explanation:
cosA =
=
=
≈ 0.55 ( to the nearest hundredth )
The concrete slab is big enough to fit the table. if the area is 36 5/6 square feet and 5 2/3 wide you can place the seven foot table length ways and it will still fit
For the first one is D
The second one is A
The third one should be B, it makes the most sence
I believe the answer would be 4ab^2