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Leviafan [203]
3 years ago
14

A concrete patio is 5 2/3 feet wide . It has an area of 36 5/6 square feet.

Mathematics
2 answers:
iVinArrow [24]3 years ago
7 0

Answer:

The length of  concrete patio is 6.5 feet, so it cannot  fit a 7-foot picnic table.

Step-by-step explanation:

A concrete patio is 5 2/3 feet wide . It has an area of 36 5/6 square feet.

\texttt{Width of concrete patio = }5\frac{2}{3}=\frac{5\times 3+2}{3}=\frac{17}{3}feet

\texttt{Area of concrete patio = }36\frac{5}{6}=\frac{36\times 6+5}{6}=\frac{221}{6}feet^2

Area of rectangle = length x width

We have

          \frac{221}{6}=\texttt{Length}\times \frac{17}{3}\\\\\texttt{Length}=\frac{221}{6}\times \frac{3}{17}=\frac{13}{2}=6.5feet

The length of  concrete patio is 6.5 feet, so it cannot  fit a 7-foot picnic table.

fgiga [73]3 years ago
5 0
The concrete slab is big enough to fit the table. if the area is 36 5/6 square feet and 5 2/3 wide you can place the seven foot table length ways and it will still fit
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Kesha threw her baton up in the air from the marching band platform during practice. The equation h(t) = −16t² + 54t + 40 gives
lapo4ka [179]

Answer:

a) 40 feet

b) 54 ft/min

c) 4 mins

Step-by-step explanation:

Solution:-

- Kesha models the height ( h ) of the baton from the ground level but thrown from a platform of height hi.

- The function h ( t ) is modeled to follow a quadratic - parabolic path mathematically expressed as:

                           h ( t ) = −16t² + 54t + 40

Which gives the height of the baton from ground at time t mins.

- The initial point is of the height of the platform which is at a height of ( hi ) from the ground level.

- So the initial condition is expressed by time = 0 mins, the height of the baton h ( t ) would be:

                         h ( 0 ) = hi = -16*(0)^2 + 54*0 + 40

                         h ( 0 ) = hi = 0 + 0 + 40 = 40 feet

Answer: The height of the platform hi is 40 feet.

- The speed ( v ) during the parabolic path of the baton also varies with time t.

- The function of speed ( v ) with respect to time ( t ) can be determined by taking the derivative of displacement of baton from ground with respect to time t mins.

                        v ( t ) = dh / dt

                        v ( t )= d ( −16t² + 54t + 40 ) / dt

                        v ( t )= -2*(16)*t + 54

                        v ( t )= -32t + 54

- The velocity with which Kesha threw the baton is represented by tim t = 0 mins.

Hence,

                        v ( 0 ) = vi = -32*( 0 ) + 54

                        v ( 0 ) = vi = 54 ft / min

Answer: Kesha threw te baton with an initial speed of vo = 54 ft/min

- The baton reaches is maximum height h_max and comes down when all the kinetic energy is converted to potential energy. The baton starts to come down and cross the platform height hi = 40 feet and hits the ground.

- The height of the ball at ground is zero. Hence,

                     h ( t ) = 0

                     0 = −16t² + 54t + 40

                     0 = -8t^2 + 27t + 20

- Use the quadratic formula to solve the quadratic equation:

                     

                    t = \frac{27+/-\sqrt{27^2 - 4*8*(-20)} }{2*8}\\\\t = \frac{27+/-\sqrt{1369} }{16}\\\\t = \frac{27+/-37 }{16}\\\\t =  \frac{27 + 37}{16} \\\\t = 4

Answer: The time taken for the baton to hit the ground is t = 4 mins

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On Tuesday, Karen finished all her chores in 3/4 of an hour. On Wednesday, she finished her chores in 5/12 of an hour. How much
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Wednesday: first we divide 60 by 12 which is 5. 5 would equal 5 minutes. now we multiply 5 by 5 which is 25. Karen finished her chores in 25 minutes.

Answer: Karen finished her chores 20 minutes faster on Wednesday than Tuesday.

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