<h3>
Answer: Choice A. x^2+9</h3>
This is a sum of squares, which cannot be factored over the real numbers. You'll need to involve complex numbers to be able to factor, though its likely your teacher hasn't covered that topic yet (though I could be mistaken and your teacher has mentioned it).
Choice B can be factored through the difference of squares rule. Therefore, choice B is not prime.
Choice C and D can be factored by pulling out the GCF and then use the difference of squares rule afterward. So we can rule out C and D as well.
Answer:
The perimeter of the square is 
Step-by-step explanation:
step 1
Find the length side of the square
we know that
The area of a square is equal to
where
b is the length side of the square
we have
substitute and solve for b
square root both sides
step 2
Find the perimeter of the square
we know that
The perimeter of the square is equal to
we have
substitute
Yes because they as fraction would be equal parts I think
Answer: P=130
2W +2L=130
2(31) + 2(34)=130
W=31
L=34
Step-by-step explanation:
P=130
2L + 2W
W=L-3
Add all of the sides together to get perimeter.
2(L-3) + 2L=130
2L-6+2L=130
4L-6+6=130+6
4L=136
4L/4=136/4
L=34
W=L-3
W=34-3
W=31
