Answer:
<h2>hope this helps!!</h2><h3>and please let me know if I'm wrong!</h3>
<h2>
Answer:</h2>
Option: C is the correct answer.
C. 
<h2>
Step-by-step explanation:</h2>
The sequence is given by the explicit formula as:
where 
is the nth term of the sequence.
Also, the first term of the sequence is: 
i.e.
Also,
Hence, the recursive formula which represents the same sequence is:
Option: C
I think this is what you are looking for:
=−12
a
b
=
−
12
+=4
a
+
b
=
4
(+)2=42
(
a
+
b
)
2
=
4
2
2+2+2=16
a
2
+
b
2
+
2
a
b
=
16
∴2+2=16+2×12=40
∴
a
2
+
b
2
=
16
+
2
×
12
=
40
Now, (−)2=2+2−2=40+2×12=64
(
a
−
b
)
2
=
a
2
+
b
2
−
2
a
b
=
40
+
2
×
12
=
64
∴(−)=64‾‾‾√=±8
∴
(
a
−
b
)
=
64
=
±
8
So, 2−2=(+)(−)
a
2
−
b
2
=
(
a
+
b
)
(
a
−
b
)
2−2=(4)(±8)=±32
a
2
−
b
2
=
(
4
)
(
±
8
)
=
±
32
Hope that helps and sorry if it is confusing!
Swap x and y's positions
f(x) is another way of saying y, so basically tha initial function is y = 1-2x^3.
Change it up to x = 1-2y^3 and solve for y
X - 1 = - 2y^3
(X - 1)/-2 = y^3
So the cube root of ((x-1)/2) = y
