1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
arsen [322]
3 years ago
5

NEED HELP ASAP!! PLEASE HELP!

Mathematics
1 answer:
Darya [45]3 years ago
7 0
The second one is correct
You might be interested in
Suppose a sample of 972972 tenth graders is drawn. Of the students sampled, 700700 read above the eighth grade level. Using the
max2010maxim [7]

Answer:

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

972 students, 700 read above the eight grade level. We want the confidence interver for the proportion of those who read at or below the 8th grade level. 972 - 700 = 272, so n = 972, \pi = \frac{272}{972} = 0.28

85% confidence level

So \alpha = 0.15, z is the value of Z that has a pvalue of 1 - \frac{0.15}{2} = 0.925, so Z = 1.44.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 - 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.259

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.28 + 1.44\sqrt{\frac{0.28*0.72}{972}} = 0.301

The 85% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.259, 0.301).

3 0
3 years ago
A fireperson needs to use a ladder of 25 feet in length to rescue a cat that has become
svp [43]

Answer:

A, because the cat is only 15 feet in the air and the TREE is 50 feet

5 0
2 years ago
What equations is equivalent to y = log x
saw5 [17]

"log" standing alone actually means "logarithm to the base 10."


Thus, y = log x   <=>   y = log      x
                                               10
                                                                           y
 Stated another way (inverse functions), x = 10
4 0
3 years ago
What is the volume, in cubic ft, of a rectangular prism with a height of 3ft, a width of 8ft, and a length of 6ft?
postnew [5]
<h3>- - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - </h3>

➷ volume = length x width x height

volume = 6 x 3 x 8

volume = 144 cubic ft

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

6 0
2 years ago
Read 2 more answers
PLEASE HELP!! look at the image below
Sladkaya [172]

Answer:

A right 4 down 5

Step-by-step explanation:

counting the grid spaces from any point for example R and going to the point R' (R prime) will give you the translation

8 0
3 years ago
Other questions:
  • What is the sum of five and four ninths and seven and five ninths
    7·2 answers
  • 12 POINTSSSS!!!
    10·1 answer
  • The winery sold 81 cases of wine this week. If twice
    9·1 answer
  • How do you solve <br> -3x+y=7 <br> 5x+2y=3<br> by substitution method??
    5·2 answers
  • At 4:00 am on Christmas Day, 1974 the eye of Cyclone Tracy was directly over Darwin. If Perth time is 1.5 hours behind Darwin ti
    8·1 answer
  • Suppose you had been in charge of designing the study. What sample size would be needed to construct a margin of error of 2% wit
    10·1 answer
  • An amount of $38,000 is borrowed for 13 years at 7% interest, compounded annually. If the loan is paid in full at the end of
    5·1 answer
  • Help with this problem pls
    7·2 answers
  • 12 wrestlers compete in a competition. If each wrestler wrestles one match with each
    13·1 answer
  • What type of number is √5?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!