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2 years ago

Please help, PLEASE will give brainlest answer

Mathematics

1 answer:

Korolek [52]2 years ago

8 0

Answer:

SteAnswer:

y = 1/2x + 3/2

Step-by-step explanation:

Using the equation of the line

y - y_1 = m ( x - x_1)

First find the slope of the line

-2x + 4y = 8

It must be in this form

y = mx + C

4y = 8 + 2x

divide through by 4

4y/4 = 8 + 2x / 4

y = 8 + 2x/4

Let's separate

y = 8/4 + 2x/4

y = 2 + 1/2x

y = 1/2x + 2

Therefore, our slope or m is 1/2

Using the equation of the line

y - y_1 = m ( x - x_1)

With point (-5, -1)

x_1 = -5

y_1 = -1

y - (-1) = 1/2(x - (-5)

y + 1 = 1/2( x + 5)

Opening the brackets

y + 1 = x + 5 / 2

y = x + 5/2 - 1

Lcm is 2

y = x + 5 / 2 - 1/1

y = x + 5 -2/2

y = x +3/2

We can still separate it

y = x /2 + 3/2

y = 1/2x + 3/2

The equation of the line is

y = 1/2x + 3/2

The correct answer is A

brainliest?

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find the area of the trapezium whose parallel sides are 25 cm and 13 cm The Other sides of a Trapezium are 15 cm and 15 CM

Snezhnost [94]

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - A trapezium ABCD with non parallel sides of measure 15 cm each ! along , the parallel sides are of measure 13 cm and 25 cm

To find - Area of trapezium

Refer the figure attached ~

In the given figure ,

AB = 25 cm

BC = AD = 15 cm

CD = 13 cm

Construction -

$draw \: CE \: \parallel \: AD \: \\ and \: CD \: \perp \: AE$

Now , we can clearly see that AECD is a parallelogram !

$\therefore$ AE = CD = 13 cm

Now ,

$AB = AE + BE \\\implies \: BE =AB - AE \\ \implies \: BE = 25 - 13 \\ \implies \: BE = 12 \: cm$

Now , In ∆ BCE ,

$semi \: perimeter \: (s) = \frac{15 + 15 + 12}{2} \\ \\ \implies \: s = \frac{42}{2} = 21 \: cm$

Now , by Heron's formula

$area \: of \: \triangle \: BCE = \sqrt{s(s - a)(s - b)(s - c)} \\ \implies \sqrt{21(21 - 15)(21 - 15)(21 - 12)} \\ \implies \: 21 \times 6 \times 6 \times 9 \\ \implies \: 12 \sqrt{21} \: cm {}^{2}$

Also ,

$area \: of \: \triangle \: = \frac{1}{2} \times base \times height \\ \\\implies 18 \sqrt{21} = \: \frac{1}{\cancel2} \times \cancel12 \times height \\ \\ \implies \: 18 \sqrt{21} = 6 \times height \\ \\ \implies \: height = \frac{\cancel{18} \sqrt{21} }{ \cancel 6} \\ \\ \implies \: height = 3 \sqrt{21} \: cm {}^{2}$

Since we've obtained the height now , we can easily find out the area of trapezium !

$Area \: of \: trapezium = \frac{1}{2} \times(sum \: of \:parallel \: sides) \times height \\ \\ \implies \: \frac{1}{2} \times (25 + 13) \times 3 \sqrt{21} \\ \\ \implies \: \frac{1}{\cancel2} \times \cancel{38 }\times 3 \sqrt{21} \\ \\ \implies \: 19 \times 3 \sqrt{21} \: cm {}^{2} \\ \\ \implies \: 57 \sqrt{21} \: cm {}^{2}$