Question

Solve the equation using the quadratic formula. 3x^2-18=-6 a) x = ± 6 b)x = ± 2 c)x = 6 d)x = 2

Answer 1

Answer: B x=+-2

Step-by-step explanation:

The Quadratic formula is -b+-$-b+-\sqrt{(b^{2} -4ac)} /2a$

First make everything equal to 0

$3x^2-18+6=0$

Then Simplify

$3x^2-12=0$

Now use the formula where a=3, b=0, and c=-12

$0+-\sqrt{0^2-4(3)(-12)$  divided by 2(3)

$0+-\sqrt{0-(-144)}/6$

$\frac{0+-12}{6}$

then we get 12/6 and -12/6 which simplified is +-2