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Juliette [100K]
3 years ago
11

PLZ HELP I WILL GIVE BRAINLIEST...

Mathematics
2 answers:
Softa [21]3 years ago
7 0

Answer:

1: 8

2: 6

3: A

4: D

Step-by-step explanation:

podryga [215]3 years ago
3 0

Answer:

1) 8

2) 6

3)  a.) Brian's sample

4) d.) Larger sample size

Step-by-step explanation:

1)  8 is the number of items in the sample

2) 6  is the number of items in the sample

3)  a.) Brian's sample as sample is bigger

4) d.) Larger sample size

The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers. So, when the sample size is bigger, mean is more accurate.

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Calculate the slope of the line going through A(-4,3) and B(0,6) PLEASE ANSWER
Alex

Answer:

6-3/0-(-4)

=3/4

Step-by-step explanation:

Given two points of a line to find the slope, we use the formula.y2-y1/x2-x1 hence the answer above. Our xs are x2=0 x=-4 y2=6 y1=3

7 0
3 years ago
58°<br> X Х<br> jsut give a quick
NARA [144]

Answer:

32

Step-by-step explanation:

The sum of the angles of a triangle is 180

58+90+x = 180

148+x = 180

x = 180-148

x=32

6 0
3 years ago
Read 2 more answers
Mr. Smith is unhappy with a 2-foot concrete walkway around the edge of his pool. He decides to put a different width around the
Nikolay [14]
The answer is\left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]   \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right]  x^{2}  x^{2}  \sqrt[n]{x}  \sqrt[n]{x}  \pi  \pi
8 0
3 years ago
A radioactive gas with a half-life of 2.4 days accidentally leaks into a room. If the radiation level is now 25% above a safe am
Gnom [1K]
Radioactive half-life is the time it takes for half an amount of radioactive material to decay into something else. In this case, it is assumed that the decay product is not radioactive or otherwise hazardous.

We must use the radioactive decay formula to determine at what time the radiation reaches a safe level.
A = Ao[e^(-0.693)(t)(t 1/2) where t 1/2 is the half-life, t is elapsed time, Ao is the original quantity, A is the future quantity.

We are given a half-life of 2.4 days , an Ao of 1.25 and an A of 1.00:

1.00 = (1.25)e^(-0.693)(2.4)t
1.00/1.25 = e^(-1.6632)t
0.8 = e^(-1.6632)t
t = 0.135 days = 3 hrs 15 min

This is the amount of time to a "safe level" using only radioactive decay, not venting or other means.
8 0
3 years ago
9³•9⁴ [?]<br>-------- • 9³ = 9<br> 9²​
Colt1911 [192]

9514 1404 393

Answer:

  9⁸

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

__

  \dfrac{9^3\cdot9^4}{9^2}\cdot9^3=9^{3+4-2+3}=\boxed{9^8}

7 0
3 years ago
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