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3 years ago

Ayden rents skates at the skate park for

Mathematics

1 answer:

kotykmax [81]3 years ago

8 0

Answer:

Step-by-step explanation:

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A recipe calls for blueberry muffins cost for 2 3/4 cup of blueberries. You are making 1/3 of the recipe. How much blueberries s

tester [92]

Answer: 8/9 cups

Step-by-step explanation:

The word 'of' means 'times' as far as fractions are concerned. In this case, we have 1/3 of 2 1/3.

First, it is a good idea to make 2 1/3 an improper fraction - as 8/3, so now we have:

1/3 of 8/3, but since 'of' means 'times' we have,

1/3 x 8/3 = 8/9

The answer is 8/9 cups.

7 0

3 years ago

Does anybody know how to do this pleas help I'm stuck

Masteriza [31]

Answer:

Step-by-step explanation:

78-30=48

48/2=24

each one is 24kg

7 0

3 years ago

Read 2 more answers

Which numbers are equivalent to 3/10

Sedbober [7]

Answer:

Multiply numerator and denominator with same number to gwt the answers . There are infinitely many numbers

3/10 × 2/2 = 6/20

3/10 × 5/5 = 15/50

3/10 × 10/10 = 30/100

And so on

8 0

3 years ago

If f(x) = 9x10 tan−1x, find f '(x).

djverab [1.8K]

Answer:

$\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

General Formulas and Concepts:

Calculus

Differentiation

Derivatives
Derivative Notation

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = 9x^{10} \tan^{-1}(x)$

Step 2: Differentiate

[Function] Derivative Rule [Product Rule]: $\displaystyle f'(x) = \frac{d}{dx}[9x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Rewrite [Derivative Property - Multiplied Constant]: $\displaystyle f'(x) = 9 \frac{d}{dx}[x^{10}] \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Basic Power Rule: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + 9x^{10} \frac{d}{dx}[\tan^{-1}(x)]$
Arctrig Derivative: $\displaystyle f'(x) = 90x^9 \tan^{-1}(x) + \frac{9x^{10}}{x^2 + 1}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

3 years ago

Find the sum 1/b^2c +b/c^2

inysia [295]

Hey! here is the answer
b³+c
b²c²

8 0

3 years ago