Question

Find the slope of the line that passes through (-33, -27) and (-32, -25).

Answer 1

Answer:

$= 2$

Step-by-step explanation:

$( - 33 \: \: \: \: - 27) = > (x1 \: \: \: \: y1) \\ ( - 32 \: \: \: \: - 25) = > (x2 \: \: \: \: y2)$

$slope \\ = \frac{y1 - y2}{x1 - x2} \\ = \frac{ - 27 - ( - 25)}{ - 33 - ( - 32)} \\ = \frac{ - 27 + 25}{ - 33 + 32} \\ = \frac{ - 2}{ - 1} \\ = 2$

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Answer 2

Answer: 2.

Step-by-step explanation:

You can find the slope between two points by using the "rise-over-run" method.

This method essentially calculates the slope as the quotient of the vertical span and horizontal span of the two points.

You can find it through this formula:

$s = \frac{y2 - y1}{x2 - x1}$

To find the slope, use two points, (x1, y1) and (x2 and y2).

For the points given, I will replace those values in the formula with (-33, -27) and (-32, -25).

$s = \frac{-27 - (-25)}{-33 - (-32)}\\\\s = \frac{-2}{-1}\\\\s = 2$

The slope of the line is 2.