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Xelga [282]
3 years ago
9

If sinx=1/5 and x terminates in the first quadrant, determine cos 2x.

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0

Hey there! I'm happy to help!

Let's think of this angle being put inside of a unit circle (a circle with a radius of one). This angle is going to stay inside the first quadrant, so all of its trigonometric ratios will be positive.

We are given that the sin of x is 1/5. To get the x by itself, we can just find the inverse sine of both sides to isolate the x.

x=sin^-1(1/5)

x≈ 11.536959

2x≈ 23.073918

Now, we just cosine this value.

cos2x≈ 0.92

I hope that this helps! Have a wonderful day!

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For the funtion f(x)= (x+7)^5, Find f^-1 (x)
quester [9]

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The inverse of function f(x)= (x+7)^5 is \mathbf{f^{-1} (x)=\sqrt[5]{x}+7}

Option A is correct option.

Step-by-step explanation:

For the function f(x)= (x+7)^5, Find f^{-1} (x)

For finding inverse of x,

First let:

y=(x+7)^5

Now replace x with y and y with x

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Now, solve for y

Taking 5th square root on both sides

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So, the inverse of function f(x)= (x+7)^5 is \mathbf{f^{-1} (x)=\sqrt[5]{x}+7}

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