Question

The angle of deperession of aPt A, as measured form the top of

Answer 1

Answer:B

Step-by-step explanation:

Given

Height of building $h=30\ m$

Angle of depression $\theta =45^{\circ}$

Suppose distance of Point A from base of building be  $x$

From diagram we can write

$\Rightarrow \tan \theta =\dfrac{h}{x}$

$\Rightarrow \tan (45^{\circ})=\dfrac{30}{x}$

$\Rightarrow 1=\dfrac{30}{x}$

$\Rightarrow x=30\ m$

So, point A is $30\ m$ from base of building