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Leokris [45]
3 years ago
10

What part of the reproductive system is highlighted

Biology
1 answer:
klemol [59]3 years ago
4 0
Epididymis would be the correct answer, can i get brainliest please

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Gestation period for monkey​
Akimi4 [234]

Answer:

for rhesus monkeys is 164days

3 0
3 years ago
Give an example ecological disturbance. Light Disturbance? Extreme Disturbance.
nalin [4]

Answer:

In contrast, major disturbances include large-scale wind events (such as tropical cyclones), volcanic eruptions, tsunamis, intense forest fires, epidemics, ocean temperature changes stemming from El Niño events or other climate phenomena, and pollution and land-use conversion caused by humans.

Explanation:

3 0
2 years ago
Which amino acid has a side chain that can form hydrogen bonds with a suitable partner?
quester [9]
Amino acids that have the possibility of participating in hydrogen bonds with suitable partners are those that have hydrophilic polar side chains.
3 0
3 years ago
When biuret solution is used as an indicator, it turns from blue to purple in the presence of which organic molecule?
Furkat [3]

Answer:

B

Explanation:

The biuret solution will turn from blue to purple when it is exposed to protein. The copper sulfate and potassium hydroxide cause the substance to become an alkaline.

5 0
3 years ago
Read 2 more answers
Alu element at the PV92 locus on Chromosome 16. In this population, 436 people have a heterozygous genotype and 102 people have
Lesechka [4]

Answer:

Explanation:

According to the exercise we can infer that for the Alu insert:

p: positive allelic frequency

q: negative allelic frequency

maintaining that the population is in equilibrium we can carry out the following formula

p + q = 1 and pp + 2pq + qq = 1

looking for the genotype frequency we clear and obtain the following data

genotype frequency of 2pq = 436/1000 = 0.436

The genotype frequency of qq = 102/1000 = 0.102

This is how we look now:

number of positive people for Alu = 1000- (436 + 102) = 1000- 538 = 46

In this way it is resolved that:

genotypic frequency of pp = 462/1000 = 0.462

  p = 0.462 + (0.436 / 2) = 0.462 + 0.218 = 0.680

q = 0.102+ (0.436 / 2) = 0.102 + 0.218 = 0.320

According to the exercise carried out it is deduced:

The value of p in the population is = 0.68

We conclude that our prognosis showing a homozygous positive genotype is: 0.462

6 0
3 years ago
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