What distinguishes the savanna and grassland biomes?the aswer is a
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Answer:
- GLYCOLYSIS :- Glycolysis is the metabolic pathway that converts glucose C₆H₁₂O₆, into pyruvic acid, CH₃COCOOH. The free energy released in this process is used to form the high-energy molecules adenosine triphosphate and reduced nicotinamide adenine dinucleotide
- PRODUCTS :- Glycolysis produces 2 ATP, 2 NADH, and 2 pyruvate molecules: Glycolysis, or the aerobic catabolic breakdown of glucose, produces energy in the form of ATP, NADH, and pyruvate, which itself enters the citric acid cycle to produce more energy.
- INPUT:- Glycolysis is the first step in cellular respiration, occurring in all living cells. Overall, the input for glycolysis is one glucose, two ATP and two NAD+ molecules giving rise to two pyruvate molecules, four ATP and two NADH.
- BREAKDOWN:- During glycolysis, glucose ultimately breaks down into pyruvate and energy; a total of 2 ATP is derived in the process (Glucose + 2 NAD+ + 2 ADP + 2 Pi --> 2 Pyruvate + 2 NADH + 2 H+ + 2 ATP + 2 H2O). The hydroxyl groups allow for phosphorylation. The specific form of glucose used in glycolysis is glucose 6-phosphate
- STAGES:-
- Reaction 1: glucose phosphorylation to glucose 6-phosphate.
- Reaction 2: isomerization of glucose 6-phosphate to fructose 6-phosphate
- Reaction 3: phosphorylation of fructose 6-phosphate to fructose 1,6-bisphosphate
- Reaction 4: cleavage of fructose 1,6-bisphosphate into two three-carbon fragments.
Explanation:
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