Sketch the region of integration for the following integral. ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ
1 answer:
Answer:
The graph is sketched by considering the integral. The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
Step-by-step explanation:
We sketch the integral ∫π/40∫6/cos(θ)0f(r,θ)rdrdθ. We consider the inner integral which ranges from r = 0 to r = 6/cosθ. r = 0 is located at the origin and r = 6/cosθ is located on the line x = 6 (since x = rcosθ here x= 6)extends radially outward from the origin. The outer integral ranges from θ = 0 to θ = π/4. This is a line from the origin that intersects the line x = 6 ( r = 6/cosθ) at y = 1 when θ = π/2 . The graph is the region bounded by the origin, the line x = 6, the line y = x/6 and the x-axis.
You might be interested in
Answer: Domain =
Range =
Step-by-step explanation:
Here, the given function,
Since log( negative number ) = not defined
Also,
Hence, f(x) is defined if x - 1 > 0
⇒ x > 1
Thus, f(x) is defined for all the values that are greater than 1,
⇒ Domain of f(x) = All real number greater than 1,
=
Now, for the interval ,
f(x) can be any real number.
Thus, the range of the given function =