What does the value of a do to the absolute value equation. Assume the slope is either 1 or -1.

I NEED HELP PLEASE, THANKS!!!

denpristay [2]

Answer:

C. 105 $mm^2$

Step-by-step explanation:

The formula for a regular polygon is:

$\frac{1}{2}pa$ → p is the perimeter and a is the apothem

$\frac{1}{2} (42)(5)$

105

3 0

3 years ago

]7. A zucchini plant in Darnell’s garden was 13 centimeters tall when it was first planted. Since then, it has grown approximate

Pani-rosa [81]

Let d be the number of days and h be the height

h = 13 + 0.6d

Answer: (a) h = 13 + 0.6d

Given height = 0.208m, find d:

0.208m = 20.8 cm

20.8 = 13 + 0.6d

0.6d = 20.8 - 13 = 7.8

d = 7.8 ÷ 0.6 = 13

Answer: (b) 13 days

5 0

3 years ago

Help me fast!!! Best answer gets brain liest

chubhunter [2.5K]

Answer:

w goes to dependent

and t goes to independent

Step-by-step explanation:

4 0

3 years ago

Find the mean, variance &a standard deviation of the binomial distribution with the given values of n and p.

MrMuchimi

A random variable following a binomial distribution over $n$ trials with success probability $p$ has PMF

$f_X(x)=\dbinom nxp^x(1-p)^{n-x}$

Because it's a proper probability distribution, you know that the sum of all the probabilities over the distribution's support must be 1, i.e.

$\displaystyle\sum_xf_X(x)=\sum_{x=0}^n\binom nxp^x(1-p)^{n-x}=1$

The mean is given by the expected value of the distribution,

$\mathbb E(X)=\displaystyle\sum_xf_X(x)=\sum_{x=0}^nx\binom nxp^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^nx\frac{n!}{x!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle\sum_{x=1}^n\frac{n!}{(x-1)!(n-x)!}p^x(1-p)^{n-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=1}^n\frac{(n-1)!}{(x-1)!((n-1)-(x-1))!}p^{x-1}(1-p)^{(n-1)-(x-1)}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\frac{(n-1)!}{x!((n-1)-x)!}p^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^n\binom{n-1}xp^x(1-p)^{(n-1)-x}$
$\mathbb E(X)=\displaystyle np\sum_{x=0}^{n-1}\binom{n-1}xp^x(1-p)^{(n-1)-x}$

The remaining sum has a summand which is the PMF of yet another binomial distribution with $n-1$ trials and the same success probability, so the sum is 1 and you're left with

$\mathbb E(x)=np=126\times0.27=34.02$

You can similarly derive the variance by computing $\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2$ , but I'll leave that as an exercise for you. You would find that $\mathbb V(X)=np(1-p)$ , so the variance here would be

$\mathbb V(X)=125\times0.27\times0.73=24.8346$

The standard deviation is just the square root of the variance, which is

$\sqrt{\mathbb V(X)}=\sqrt{24.3846}\approx4.9834$

7 0

3 years ago

Fill in the missing number.3 meters=______cm

Brut [27]

Answer:

300

Step-by-step explanation:

there are 100 cm in a meter (I believe)

8 0

3 years ago

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