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3 years ago

5

Can someone help me with this

2 answers:

maxonik [38]3 years ago

5 0

Answer:

$x = 9$

Step-by-step explanation:

$- 9x + 1 = - 80 \\ - 9x = - 80 - 1 \\ - 9x = - 81 \\ \frac{ - 9x}{ - 9} = \frac{ - 81}{ - 9} \\ x = 9$

Elenna [48]3 years ago

4 0

Answer: x = 9

Explanation:

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Step-by-step explanation:

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3 years ago

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A universal set U consists of elements. If sets A, B, and C are proper subsets of U and n(U), n(A B)n(A C)n(B C), n(A

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Answer:

$n(A\ u\ B) = 10$

$n(A'\ u\ C) = 10$

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Step-by-step explanation:

Given

$n(U) = 12$

$n(A\ n\ B) =n(A\ n\ C) = n(B\ n\ C) =6$

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Required

Solve a, b and c

There are several ways to solve this; the best is by using Venn diagram (see attachment for diagram)

Solving (a):

$n(A\ u\ B)$

This is calculated as:

$n(A\ u\ B) = n(A) + n(B) - n(A\ n\ B)$

From the attachment

$n(A) = 0+2+4+2 = 8$

$n(B) = 0+2+4+2 = 8$

$n(A\ n\ B) = 4 +2 = 6$

So:

$n(A\ u\ B) = 8 + 8 - 6$

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Solving (b):

$n(A'\ u\ C)$

This is calculated as:

$n(A'\ u\ C) = n(A') + n(C) -n(A'\ n\ C)$

From the attachment

$n(A) = n(U) - n(A) = 12 - 8 = 4$

$n(C) = 0+2+4+2 = 8$

$n(A'\ n\ C) = 2$

So:

$n(A'\ u\ C) = 4 + 8 - 2$

$n(A'\ u\ C) = 10$

Solving (c):

$n(A\ n\ B)'$

This is calculated as:

$n(A\ n\ B)' = n(U) - n(A\ n\ B)$

$n(A\ n\ B)' = 12- 6$

$n(A\ n\ B)' = 6$

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3 years ago

Would anyone happen to know the answer to this? :)

kow [346]

A I truly believe!! :)))

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An office opens at 9am and closes at 5.30pm with a lunch break of 30minutes. What is the ratio of lunch break to the total perio

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Answer:

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Step-by-step explanation:

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Please check if the question is worded correctly, just in case. Because ratio questions are usually based on a part and the remaining parts of the same thing, and not part to whole.

Anyway. The answer given if for the question you have typed.

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4 years ago

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