Question

Find the​ z-scores for which 3​% of the​ distribution's area lies between -z and z.

Answer 1

Answer:

The​ z-scores for which 3​% of the​ distribution's area lies between -z and z is z=0.03761.

Step-by-step explanation:

We have to find the z-score z* for which the following condition is satisfied:

$P(z$

This means that half of the area is at the left of the mean and half is at the right, so we have:

$P(0$

Then, we have:

$P(z$