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den301095 [7]
3 years ago
10

IF J is between C and T, find the value of x and JT. CJ=8x+5, CT=55, and JT=4x+2

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Answer:

<h2>x = 4</h2><h2>JT = 18</h2>

Step-by-step explanation:

Given three points J, C and T on a line, if J is between C and T then;

CJ + JT = CT.

Given CJ=8x+5, CT=55, and JT=4x+2, substituting this parameters in the equation above will give;

(8x+5)+(4x+2)= 55\\8x+4x+5+2 = 55\\12x+7 = 55\\12x = 55-7\\12x = 48\\ x = \frac{48}{12} \\x = 4

SInce JT = 4x+2

JT = 4(4)+2\\JT = 16+2\\JT = 18

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poizon [28]

Answer:

9 & 1/4

Step-by-step explanation:

you have 3/4 and you subtract by 10, and since 3/4 is a decimal (0.75) you subtract it by 10 wich gives you 9 & 1/4

7 0
3 years ago
Read 2 more answers
Which option is an example of an experiment?
son4ous [18]

option D recording the reaction time of participants in a study who were asked to press a button age as soon as they see a certain picture on a screen ASAP please

7 0
3 years ago
It takes Cindy 3/4 of an hour to complete a puzzle how many puzzles can Cindy finish in three hours
valina [46]

Answer:

She can finish 4 puzzles.

Step-by-step explanation:

3/4+3/4=1 1/2

1 1/2+ 1 1/2= 3(hours)

That means that there are four 3/4s and that also means she does 4 puzzles in 3 hours.

Hope this helps!^_^

3 0
3 years ago
Solve the equation 2^(2x+1)+8=17×2^x.
myrzilka [38]
Oooh, looks fun

ok
erm
we might want to know some properties
(x^m)(x^n)=x^{m+n}
(a^b)^c=a^{bc}
if a^m=a^n where a=a, then assume m=n

2^{2x+1}=(2^{2x})(2^1)
so
(2^{2x})(2)+8=17(2^x)
(2^{2x})(2)+2^3=17(2^x)
(2^x)^2(2)+2^3=17(2^x)
minus 17*2^x both sides
(2^x)^2(2)+2^3-17(2^x)=0
use u subsitution, u=2ˣ
(u)^2(2)+2^3-17(u)=0
solve 2u^2+8-17u=0
or
2u^2-17u+8=0
ac method
2 times 8=16
what 2 number multiply to get -17 and add to get 16
-16 and -1
2u²-1u-16u+8=0
(2u²-1u)+(-16u+8)=0
u(2u-1)+(-8)(2u-1)=0
(u-8)(2u-1)+0
u-8=0
u=8

2u-1=0
2u=1
u=1/2

now
u=2ˣ

8=2ˣ
2^3=2^x
3=x

and
\frac{1}{2}=2^x
2^{-1}=2^x
-1=x

x=-1 and 3
neat problem
8 0
3 years ago
Brad sold candy bars and cookies for a fundraiser at school. Candy bars sold for $3, and cookies sold for $5. He sold a total of
Stolb23 [73]
He sold 12 candy bars.
3x + 5y = 76
X + y = 20
2y= 16
Y= 8
X= 20 - 8= 12
Hope this helps.
7 0
3 years ago
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