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Vitek1552 [10]
3 years ago
11

If 4 is a solution to x^2+bx-12=0, then b=?

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer:

b = -1

Step-by-step explanation:

First plug in 4 for each x:

x^2+bx-12=0\\(4)^2+b(4)-12=0

Then simplify by multiplying out what you can with 4:

(4)^2+b(4)-12=0\\16+4b-12=0

After simplify further by combining like terms:

16+4b-12=0\\4b +4=0

Then isolate b on one side by subtracting 4 from each side:

4b+4=0\\(-4)+4b+4=0+(-4)\\4b=-4

Finally isolate b further by dividing each side by 4 to get b alone and find the answer:

4b=-4\\\frac{4b}{4}=\frac{-4}{4} \\ b=-1

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