Answer: If this population were in equilibrium and if the sickle-cell allele is recessive, the proportion of the population susceptible to sickle-cell anemia under typical conditions should be 0.20
Explanation: Hardy-Weinberg law provides an equation to relate genotype frequencies and allele frequencies in a randomly mating population. The equation is;
p² + 2pq + q² = 1
For 2 alleles such as A and a, where
p² = homozygous dominant
q² = homozygous recessive and
2pq = heterozygous
From the question, it is said that the sickle-cell allele (SS) constitutes 20% (that is, 20/100) of the hemoglobin alleles in the human gene pool and it is also said to be the homozygous recessive allele.
Therefore, q² = 20/100 = 0.20
Answer:
It is the place where blood cells are produced.They are made up of two types of stem cells: hemopoietic and stromal.
Hemopoietic can produce the blood cells
Stromal can produce fat, cartilage, and bone
Explanation:
These two statements imply that an entity is considered as a living organism has at least one cell (the basic unit of life). It could be eucaryote or procaryote, unicellular or pluricellular. It has his own metabolism and its own genetic material.
Prions, viruses, and bacteriophages are not considered as a living organism, because they are technically not a cell, and does not all the property and the structure of a cell.
No not at all , matter of fact it has never been.
