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katrin2010 [14]
4 years ago
5

O nome científico do leão é panthera leo, do gato é Felis domestcus. Os dois animais pertencem a diferentes: A:Filos B:Famílias

C:Ordens C:Espécies E:Reinos
Biology
1 answer:
STatiana [176]4 years ago
8 0
I believe the answer is : C ) Espécies

-Hope this helps.
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In eukaryotes, DNA is organized into_________which considerably complicates DNA-protein interactions during gene regulation.
lukranit [14]

Answer:

chromosomes

Explanation:

6 0
3 years ago
Your answer is CORRECT. Archaea that live by black smokers at hydrothermal vents under the ocean are often A) anaerobic due to t
Liula [17]
<h2>(A) is the correct option  </h2>

Explanation:

  • Hydrothermal vents, also known as deep sea vents are the aftermath of a volcanic eruption due to shifting of the plates that form the Earth’s crust
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3 0
4 years ago
g Which of the following statements is NOT true? A. Each variable site of a gene tree can be treated as an independent character
Lady bird [3.3K]

Answer:

C. Gene trees are only useful studying the relationships of sequences from different species.

Explanation:

Gene tree traces the evolutionary history of a particular gene. It includes all the events like duplication and speciation. It helps to study the relationship of genes from different species. Often these are orthologous genes which came form the same ancestor and code for the same protein indifferent species. Gene tree also helps to study the relationship of genes in the same species. Often these are paralogous genes which evolved by duplication and code for similar but not identical proteins in the same species. Hence, the statement that gene trees are only useful for studying the relationships of sequences from different species is incorrect.

3 0
3 years ago
You are testing a new sugar replacement that you think is indigestible (and potentially useful in diet products). You feed 1 gra
enyata [817]

Answer: The % digestibility of the sugar alternative is 10.

Explanation:

First we have to know how many grams of the sugar replacement were in the total rat feces. We know 22,5% of the feces were the sugar replacement, so we use cross multiplication for that:

If 20 grams is 100% of the feces, then

x grams / 22.5% = 20grams / 100%

xgrams = (22.5 . 20grams) / 100% = 4.5grams

If each rat ingested 1gram of the sugar replacement, all five rats ate a total of 5grams.

Now we have to check how much of this sugar replacement was digested. If the rats ate 5grams and 4.5grams were present in their feces

5grams - 4.5grams = 0.5grams

This means they digested 0.5grams.

We use cross multiplication again to find out which percentage of the initial sugar replacement this represents.

If 5grams is 100% of the ingested sugar replacement, then

x% / 0.5grams = 100% / 5grams

x% = (0.5grams . 100%) / 5grams = 10%

5 0
3 years ago
Explain how you test sand sifting plastics
sveticcg [70]

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3 years ago
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