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photoshop1234 [79]
3 years ago
15

There are two squares with integer side lengths a and b. The perimeter of the entire figure is 86 cm, and the sum of the areas o

f the two squares is 386 cm^2. In centimeters, what is the value of a+b?

Mathematics
1 answer:
7nadin3 [17]3 years ago
3 0

Answer:

24

Step-by-step explanation:

4a+2b= 86 cm

a²+b²= 386 cm²

a+b=?

----------

  • 4a+2b= 86  
  • 2a+b= 43
  • (2a+b)²=43²
  • 4a²+4ab+b²=1849

b²= 386- a², b= 43- 2a

  • 4a²+4a(43-2a)+386-a²-1849=0
  • 4a²+172a-8a²-a²-1463=0
  • -5a²+172a-1463=0
  • 5a²-172a+1463=0

solving quadratic equation we get

a=19 - integer solution

b= 43-2*19= 5

a+b=19+5=24

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PSYCHO15rus [73]

cos (2x) = cos x

2 cos^2 x -1 = cos x   using the double angle formula

2 cos ^2 x -cos x -1 =0

factor

(2 cos x+1) ( cos x -1) = 0

using the zero product property

2 cos x+1 =0    cos x -1 =0

2 cos x = -1       cos x =1

cos x = -1/2       cos x=1

taking the arccos of each side

arccos cos x = arccos (-1/2)         arccos cos x = arccos 1

x = 120 degrees   x=-120   degrees           x=0

remember you get 2 values ( 2nd and 3rd quadrant)

these are the principal values

now we need to add 360

x = 120+ 360n      x=-120+ 360n      x = 0 + 360n  where n is an integer


3 0
3 years ago
Solve the following congruence equations for X a) 8x = 1(mod 13) b) 8x = 4(mod 13) c) 99x = 5(mod 13)
xxMikexx [17]

Answer:

a) 5+13k  where k is integer

b) 20+13k where k is integer

c)12+13k where k is integer

Step-by-step explanation:

(a)

8x \equiv 1 (mod 13) \text{ means } 8x-1=13k.

8x-1=13k

Subtract 13k on both sides:

8x-13k-1=0

Add 1 on both sides:

8x-13k=1

I'm going to use Euclidean Algorithm.

13=8(1)+5

8=5(1)+3

5=3(1)+2

3=2(1)+1

Now backwards through the equations:

3-2=1

3-(5-3)=1

3-5+3=1

(8-5)-5+(8-5)=1

2(8)-3(5)=1

2(8)-3(13-8)=1

5(8)-3(13)=1

So compare this to:

8x-13k=1

We see that x is 5 while k is 3.

Anyways 5 is a solution or 5+13k is a solution where k is an integer.

b)

8x \equiv 4 (mod 13)

8x-4=13k

Subtract 13k on both sides:

8x-13k-4=0

Add 4 on both sides:

8x-13k=4

We got this from above:

5(8)-3(13)=1

If we multiply both sides by 4 we get:

8(20)-13(12)=4

So x=20 and 20+13k is also a solution where k is an integer.

c)

[tex]99x \equiv 5 (mod 13)[/tex

99x-5=13k

Subtract 13k on both sides:

99x-13k-5=0

Add 5 on both sides:

99x-13k=5

Using Euclidean Algorithm:

99=13(7)+8

13=8(1)+5

Go back through the equations:

13-8=5

13-(99-13(7))=5

8(13)-99=5

99(-1)+8(13)=5

Compare this to 99x-13k=5 and see that x=-1 or -1+13=12 or 12+13k is a solution where k is an integer.

8 0
2 years ago
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nataly862011 [7]

Answer:

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Step-by-step explanation:

18+6+4=28

8 0
3 years ago
What binomial must he added to (3r+14) to make the sum of the two polynomials equal (8r-6)
rodikova [14]

Answer:

(5r - 20)

Step-by-step explanation:

(3r + 14) + (Ar + B) = (8r - 6)

B = -6 - 14 = -20

A = 8 - 3 = 5

4 0
2 years ago
Solve each proportion ; b/5= 8/16 ( those are fractions)
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The answer is 2.5 just set it up and cross multiply then divide 
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