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3 years ago

Suppose you take the small prism and stack it on top of the larger prism. What will be the volume of the composite figure

Mathematics

1 answer:

sergeinik [125]3 years ago

4 0

You didn't provide a picture, but if your problem is like the one in my workbook, I might be able to help.

Find the volume of the first figure, then find the volume of the second figure, then add them together.

V=lwh

V(1)=(15)(12)(6)

= 1,080in^3

V(2)=(12)(6)(6)

= 432in^3

--------------------------------------------

1,080+432= 1,512 in^3

--------------------------------------------

Your answer should be 1,512

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Paola made a rectangular painting that has an area of 24 square feet. He now wants to make a similar

BigorU [14]

Answer:
D.) 10 2/3 square feet
Step-by-step explanation:
The area will change by
multiply the area by 4/9 and you get 32/3 = 10 and 2/3 (because 10 = 30/3)

4 0

1 year ago

Solve each inequality, and then drag the correct solution graph to the inequality.

Nesterboy [21]

The correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

(NOTE: The graphs are labelled A, B and C from left to right)

For the first inequality,

$4(9x-18)>3(8x+12)$

First, clear the brackets,

$36x-72>24x+36$

Then, collect like terms

$36x-24x>36+72\\12x >108$

Now divide both sides by 12

$\frac{12x}{12} > \frac{108}{12}$

∴ $x > 9$

For the second inequality

$-\frac{1}{3}(12x+6) \geq -2x +14$

First, clear the fraction by multiplying both sides by 3

$3 \times[-\frac{1}{3}(12x+6)] \geq3 \times( -2x +14)$

$-1(12x+6) \geq -6x +42$

Now, open the bracket

$-12x-6 \geq -6x +42$

Collect like terms

$-6 -42\geq -6x +12x$

$-48\geq 6x$

Divide both sides by 6

$\frac{-48}{6} \geq \frac{6x}{6}$

$-8\geq x$

∴ $x\leq -8$

For the third inequality,

$1.6(x+8)\geq 38.4$

First, clear the brackets

$1.6x + 12.8\geq 38.4$

Collect likes terms

$1.6x \geq 38.4-12.8$

$1.6x \geq 25.6$

Divide both sides by 1.6

$\frac{1.6x}{1.6}\geq \frac{25.6}{1.6}$

∴ $x \geq 16$

Let the graphs be A, B and C from left to right

The first graph (A) shows $x\leq -8$ and this matches the 2nd inequality

The second graph (B) shows $x \geq 16$ and this matches the 3rd inequality

The third graph (C) shows $x > 9$ and this matches the 1st inequality

Hence, the correct solution graph to the inequalities are

$4(9x-18)>3(8x+12)$ → C

$-\frac{1}{3}(12x+6) \geq -2x +14$ → A

$1.6(x+8)\geq 38.4$ → B

Learn more here: brainly.com/question/17448505

8 0

2 years ago

PLS HELP QUICKKKKK! Tap the photo to see the full problem. Answer all 3 questions please and I'll give brainliest if it is right

Ghella [55]

3x + 8 = 3x + []

Subtract 3x from both sides.

[] = 8

If you want no values of x, it can be any positive value other than 8.
If you want all values of x, the value must be 8.
If you want only one value of x, it is impossible because both equations have the same slope.

4 0

2 years ago

Me groves has trays of paint for her students. Each tray has 5 colors. One of the colors is purple. What fraction of the colors

Natali5045456 [20]

Purple = 1/5 of the colors

5 colors per tray, 20 trays = 5 * 20 = 100 colors

1/5 * 100 = 100/5 = 20

20 colors are purple

20/100 = 1/5

1/5

7 0

3 years ago

A rectangular picture frame has side lengths of 12 in by 9.5 in what is the length of the diagonal of the picture

OleMash [197]

Answer:

Length of diagonal of picture = 15.30 inches

Step-by-step explanation:

Given that:

Side lengths of picture frame = 12 inches by 9.5 inches

As the picture is rectangular, the diagonal will form hypotenuse of right angled triangle.

Using Pythagorean theorem;

a²+b²=c²

Putting the values in the theorem

$(12)^2 + (9.5)^2 = c^2 \\144+90.25=c^2\\c^2 = 234.25$

Taking square root on both sides

$\sqrt{c^2}=\sqrt{234.25}\\c=15.30$

Hence,

Length of diagonal of picture = 15.30 inches

3 0

2 years ago