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3 years ago

Find the vertex of y=x^2-2x+3

Mathematics

1 answer:

Archy [21]3 years ago

5 0

Answer:

y = x^2 - 2x + 3

The vertex has x component which is the solution of equation:

y' = 0

<=>2x - 2 = 0

<=> x = 1

Substitute x = 1 back into original equation y = x^2 - 2x + 3, then

y = 1^2 - 2*1 + 3 = 1 - 2 + 3 = 2

=> Vertex(1, 2)

Hope this helps!

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Help please I'm stuck show and explain your work

Deffense [45]

The expressions D, E, and F represent a correct solution to the equation.

Step-by-step explanation:

Step 1:

First, we need to solve the given equation and find the value of x which satisfies the equation.

$6(x+4)=20, (x+4) = \frac{20}{6} = 3.333,$

$x = 3.333 - 4 = -0.666.$

So the value of x for the given equation is -0.666.

Step 2:

Now we evaluate the values of the six given options to see which ones have an x value of -0.666.

A. $\frac{20-4}{6}= \frac{16}{6} = 2.666,$

B. $\frac{1}{6} (20-4)= \frac{1}{6} (16)=\frac{16}{6} = 2.666,$

C. 20 -6 -4 = 20 - 10 = 10.

D. $\frac{20}{6} -4= 3.333 - 4 = -0.666,$

E. $\frac{1}{6} (20-24) = \frac{1}{6} (-4)= -0.666,$

F. $(20-24)\frac{1}{6} = (-4)\frac{1}{6} = -0.666.$

So the options D, E, and F represent a correct solution to the given equation.

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Step-by-step explanation:

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