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Elden [556K]
2 years ago
10

Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque

ncy distribution. Also identify the number of individuals included in the summary. Blood Platelet Count of Females​ (1000 ​cells/mu​L) Frequency 100​-199 24 200​-299 90 300​-399 27 400​-499 1 500​-599 4 Identify the lower class limits. nothing​, nothing​, nothing​, nothing​, nothing ​(Type integers or decimals. Do not round. Use ascending​ order.) Identify the upper class limits. nothing​, nothing​, nothing​, nothing​, nothing ​(Type integers or decimals. Do not round. Use ascending​ order.) Identify the class width. nothing ​(Type an integer or a decimal. Do not​ round.) Identify the class midpoints. nothing​, nothing​, nothing​, nothing​, nothing ​(Type integers or decimals. Do not round. Use ascending​ order.) Identify the class boundaries. nothing​, nothing​, nothing​, nothing​, nothing​, nothing ​(Type integers or decimals. Do not round. Use ascending​ order.) Identify the number of individuals included in the summary. nothing ​(Type a whole​ number.) Enter your answer in each of the answer boxes.
Mathematics
2 answers:
skad [1K]2 years ago
8 0

Answer: this makes no sence to me

Step-by-step explanation:

maw [93]2 years ago
3 0

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

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Feliz [49]
I fear that there is an error copying your assignment.  
65% of the students walked.  Are all of the other students on buses?  Are there both public buses AND private buses?
Assuming that you need to know BOTH kinds of buses, try this:

65% of the students walked, so since 100% - 65% = 35% then this means that 35% of the students were on buses.
Since we know that there are 360 more walkers than bus riders, then one equation we know is:  65% of S = 360 + 35% of S  (let S = total # of students)
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           <u> - .35 S   </u>  =     <u>   - .35 S</u>      Subtract .35 S from both sides
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                      S   =  1,200  so we know that this is the total number of students, but that is not what was asked.  
They want to know how many are on buses and specifically how many are on public buses, if I read this correctly.
   Since the walkers = 65% of 1,2000 and we know of means TIMES, then
                                  .65 (1,200) =  780 walkers
 1,200 total students minus 780 walkers = 420 bus riders

Now, if there is not a misprint and we really have to figure out the public bus riders as compared to the private bus riders, then remember the ratio from above in the question:   4 bus: 3 public buses
Now if I read this right, that means that 3/4ths of the bus riders were on public buses
so 3/4 of 420 means 3/4 times 420  = 3 times 105 = 315 public bus riders (which coincidentally leaves 105 private bus riders, but since they are private we don't know much about them.  Ha-Ha..... I made a lame joke.)

So your answer is 315 public bus riders



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