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tatyana61 [14]
3 years ago
7

Seth has game and education apps on his tablet . He noticed that he has 5 game apps for every 2 education apps . Which of the fo

llowing is another way to write this ratio ?
Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

you could write it as 5:2  & you could also write it as 2:5

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What is the average rate of change of the function f(x)=20(14)x from x = 1 to x = 2? Enter your answer, as a decimal, in the box
Lesechka [4]

Answer: -3.75

Step-by-step explanation:

10000000000% sure because I took the test

5 0
3 years ago
Read 2 more answers
Miles brought the Russian novel Anna Kerenina. His paperback edition contains 992 page. Miles takes 3 days to read the first 50
Nesterboy [21]

Answer:

59.52 days

Step-by-step explanation:

So this is a simple problem we can solve easily

If it takes 3 days to read 50 pages then obviously his rate of reading is 50 pages per day

If we divide 992 by 50, then we can find how many 3 day increments it will take him

(992/50 is 19.84)

Now is we multiply 19.84 by 3, we get the total amount of days which is 59.52

I hope I helped and have a wonderful day!

7 0
2 years ago
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
2 years ago
Read 2 more answers
The perimeter of AABC is 13 cm. It was dilated to
Marina86 [1]

Answer:

you answer will be D. 52 cm.

Step-by-step explanation:

Hope it helps

7 0
2 years ago
Your answer must be simplified. x−24≥9
Harrizon [31]

Answer:

x>=33

Step-by-step explanation:

x-24>=9

x>=24+9

x>=33

4 0
3 years ago
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