Given:
A spinner marked A, B, C is spun then a 6-sided die is rolled.
To find:
The probability of getting a B and then a 6.
Solution:
We know that,

Total possible values for a spinner are 3. So, the probability of getting B, we get

Total possible values for a die are 6. So, the probability of getting 6, we get

Now, the probability of getting a B and then a 6 is


The required probability is
.
Therefore, the correct option is D.
<span>-3|15 - s| + 2s^3 when s = -3 is
</span>-3|15 - (-3)| + 2(-3)^3 = <span>-3|15 + 3| + 2(-27) = </span><span>-3|18| + (-54) = -3(18) - 54 = -54 - 54 = -108</span>
Answer:
The probability is
≅ 
Step-by-step explanation:
Let's analyze the question.
There are 15 students in the 8th grade.
The students are randomly placed into three different algebra classes of 5 students each.
We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.
One possible way to solve this question is to think about the product probability rule.
We can use it because we are in an equiprobable space. (And also the events are independent).
Let's set for example a class for Evan.
The probability that Evan will be in a class is 
Then for Terry there are
places out of
that puts Terry in the Evan's class.
We write 
Finally for Trevor there are
places out of the remaining
that puts Trevor in the same class with Evan and Terry.
Using the product rule we write :

The probability of the event is
≅ 
Pi*radius squared= area of a circle
3.14*2^2=12.56yd^2
pi*diameter=circumference
3.14*4=12.56yd
area of surface around the cylinder=circumference*height
12.56*6=75.36yd^2
area of surface around the cylinder+ (area of circle*2)= surface area
75.36+(12.56*2)=100.48
the answer should by 100.48 yards squared
hope this helps