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Leokris [45]
3 years ago
10

Hello All,

Mathematics
1 answer:
Lisa [10]3 years ago
8 0

Answer: (going down the table)

1) 5, 8, 6, 1

2) 2, 6, 10, 2

Step-by-step explanation:

count how many are in that bracket.

EG:

1) the amount of numbers between 5 and 10, including 5

etc

You might be interested in
A spinner marked A, B, C is spun then a 6-sided die is rolled. What is the probability of getting a B and then a 6.
BigorU [14]

Given:

A spinner marked A, B, C is spun then a 6-sided die is rolled.

To find:

The probability of getting a B and then a 6.

Solution:

We know that,

\text{Probability}=\dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

Total possible values for a spinner are 3. So, the probability of getting B, we get

P(B)=\dfrac{1}{3}

Total possible values for a die are 6. So, the probability of getting 6, we get

P(6)=\dfrac{1}{6}

Now, the probability of getting a B and then a 6 is

P(B,6)=\dfrac{1}{3}\times \dfrac{1}{6}

P(B,6)=\dfrac{1}{18}

The required probability is \dfrac{1}{18}.

Therefore, the correct option is D.

5 0
2 years ago
What is the value of -3|15 - s| + 2s3 when's = -3
slamgirl [31]
<span>-3|15 - s| + 2s^3 when s = -3 is
</span>-3|15 - (-3)| + 2(-3)^3 = <span>-3|15 + 3| + 2(-27) = </span><span>-3|18| + (-54) = -3(18) - 54 = -54 - 54 = -108</span>
6 0
3 years ago
What is the value of y?<br> 3/3 units <br> 6/3 units<br> 9/3 units<br> 12/3 units
vesna_86 [32]
9/3 units hope it helps
4 0
3 years ago
There are 15 students in the 8th grade. The students are randomly placed into three different algebra classes of 5 students each
xeze [42]

Answer:

The probability is   \frac{6}{91} ≅ 0.0659

Step-by-step explanation:

Let's analyze the question.

There are 15 students in the 8th grade.

The students are randomly placed into three different algebra classes of 5 students each.

We are looking for the probability that Trevor, Terry and Evan will be in the same algebra class.

One possible way to solve this question is to think about the product probability rule.

We can use it because we are in an equiprobable space. (And  also the events are independent).

Let's set for example a class for Evan.

The probability that Evan will be in a class is 1

Then for Terry there are 4 places out of 14 that puts Terry in the Evan's class.

We write 1.\frac{4}{14}

Finally for Trevor there are 3 places out of the remaining 13 that puts Trevor in the same class with Evan and Terry.

Using the product rule we write :

1.\frac{4}{14}.\frac{3}{13}=\frac{6}{91}

The probability of the event is \frac{6}{91} ≅ 0.0659

5 0
3 years ago
Find the surface of a cylinder with a base diameter of 4yd and a height of 6yd
yuradex [85]
Pi*radius squared= area of a circle
3.14*2^2=12.56yd^2

pi*diameter=circumference
3.14*4=12.56yd

area of surface around the cylinder=circumference*height
12.56*6=75.36yd^2

area of surface around the cylinder+ (area of circle*2)= surface area
75.36+(12.56*2)=100.48

the answer should by 100.48 yards squared

hope this helps
3 0
3 years ago
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