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3 years ago

12

Mike is tiling his kitchen floor. Each tile costs $1.79 and covers 2.25 square feet. If

2 answers:

vova2212 [387]3 years ago

4 0

Step-by-step explanation:

First, let's find out how many tiles Mike needs.

Mike's kitchen is 75sqft, each tile covers 2.25sqft, so 75sqft/2.25sqft=33.3333...,

multiply that number by the cost per tile and round to the nearest hundredth.

Arisa [49]3 years ago

4 0

75 is the total area of the floor, so divide that by how much square feet one tile covers.
75/2.25=33.3
You want to round up to the nearest whole number because you need that extra little 1/3 of tile to cover the whole floor. Make sure you NEVER round down. So now you would need 34 tiles after rounding up.

Next, multiply how many tiles you need by the cost of one tile.
34x1.79=$60.86

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Mashutka [201]

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3 years ago

A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c

mihalych1998 [28]

Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

So

$P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75$

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

$P(A \cap B) = 0.6*\frac{1}{6} = 0.1$

Find the probability that bridge B was used.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333$

0.1333 = 13.33% probability that bridge B was used.

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3 years ago

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3 years ago

Please help me also explain your answer so I can get better at this thank you :)

Elina [12.6K]

Answer: 880

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2 years ago

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My name is Ann [436]

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3 years ago