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2 years ago

Find the minimum value of the function f(x) = 2x2 – 17.3x + 32 to the nearest hundredth.

Mathematics

1 answer:

Klio2033 [76]2 years ago

5 0

Answer:

5600.014

= 5000 + 600 + 0.010 + 0.004

i am a mathematics teacher. if anything to ask please pm me

Step-by-step explanation:

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Gekata [30.6K]

Answer:

The answer is C I believe

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Convert 28/50to a percent

velikii [3]

The answer is 56%
You first divide 28 by 50=.56, then since it's a decimal, you move the decimal twice to the right to make a percentage=56%

3 0

3 years ago

What is the median of the set of data 928, 834, 842, 841, 932, 917, 892, 856, 908, 867, 873, 868, 872, 921, and 924?

Aleksandr-060686 [28]

Median: 873
Mean: 885

3 0

2 years ago

What is thesum of the two polynomials ? (-x^2+9)+(-3x^2-11x+4)

True [87]

-x^2 + 9 - 3x^2 - 11x + 4
-4x^2 - 11x + 13

3 0

2 years ago

PLS TRY TO ANSWER ASAP.

Harrizon [31]

Answer:

0.075 m/min

Explanation:

You need to use derivatives which is an advanced concept used in calculus.

1. Write the equation for the volume of the cone:

$V=\dfrac{1}{3}\pi r^2h$

2. Find the relation between the radius and the height:

r = diameter/2 = 5m/2 = 2.5m

h = 5.2m

h/r =5.2 / 2.5 = 2.08

3. Filling the tank:

Call y the height of water and x the horizontal distance from the axis of symmetry of the cone to the wall for the surface of water, when the cone is being filled.

The ratio x/y is the same r/h

x/y=r/h

y = x . h / r

The volume of water inside the cone is:

$V=\dfrac{1}{3}\pi x^2y$

$V=\dfrac{1}{3}\pi x^2(2.08)\cdot x\\\\\\V=\dfrac{2.08}{3}\pi x^3$

4. Find the derivative of the volume of water with respect to time:

$\dfrac{dV}{dt}=2.08\pi x^2\dfrac{dx}{dt}$

5. Find x² when the volume of water is 8π m³:

$V=\dfrac{2.08}{3}\pi x^3\\\\\\8\pi=\dfrac{2.08}{3}\pi x^3\\\\\\ 11.53846=x^3\\ \\ \\ x=2.25969\\ \\ \\ x^2=5.1062$ m²

6. Solve for dx/dt:

$1.2m^3/min=2.08\pi(5.1062m^2)\dfrac{dx}{dt}$

$\dfrac{dx}{dt}=0.03596m/min$

7. Find dh/dt:

From y/x = h/r = 2.08:

$y=2.08x\\\\\\\dfrac{dy}{dx}=2.08\dfrac{dx}{dt}\\\\\\\dfrac{dy}{dt}=2.08(0.035964m/min)=0.0748m/min\approx0.075m/min$

That is the rate at which the water level is rising when there is 8π m³ of water.

4 0

2 years ago