Answer:
A function is a relation that maps inputs from a set called the domain, into outputs from a set called the range.
Such that each input can be mapped into only one output.
So for example, if we have a relation that maps the input 2 into two different values:
f(2) = 4
f(2) = 8
Then this is not a function.
In the case of the problem, we have a student as the input, and the hair color as the output.
So we will have something like:
f(student) = blond
And if this student decides to change his/her hair color to red?
Then the function becomes:
f(student) = red
So for the same input, we had two different outputs, which means that this is not a function.
We also could have the case where a given student has two colors (Californian for example)
Where again, we would see two different outputs for one single input.
Answer:
(-2, -4), (-1, -1), (0, 0), (1, -1), (2, -4)
Step-by-step explanation:
You plug in x values to get the y values are dot-in the points!
y = -x^2
You plug in -2 and get -(2)^2 = -(4) = -4
Same thing with all other values.
This question is incomplete, the complete question is;
An aircraft seam requires 27 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with the same probability. (Round your answers to four decimal places.)
If 25% of all seams need reworking, what is the probability that a rivet is defective?
Answer:
the probability that a rivet is defective is 0.0106
Step-by-step explanation:
Given the data in the question,
let event X represent seam fails and event B represent rivet fails.
now, 25% of all seams need reworking;
i.e P(X) = 25% = 0.25
the probability that a rivet is defective will be;
P( A ) = 1 - P( B' )²⁷
so
0.25 = 1 - P( B' )²⁷
P( B' )²⁷ = 1 - 0.25
P( B' )²⁷ = 0.75
P( B' ) =
P( B' ) = 0.9894
so
P( B ) = 1 - 0.9894
P( B ) = 0.0106
Therefore, the probability that a rivet is defective is 0.0106
Answer:
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