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leva [86]
3 years ago
7

Define polynomial with some examples.

Mathematics
2 answers:
Katena32 [7]3 years ago
7 0
<h2><em>Polynomial</em></h2>

<em>An</em><em> </em><em>algebr</em><em>aic</em><em> </em><em>express</em><em>ion</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>form</em><em> </em><em>of</em><em> </em><em>a0</em><em>+</em><em>a1x</em><em>+</em><em>a2x2</em><em>+</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>+</em><em>anx^</em><em>n</em><em>,</em><em>where</em><em> </em><em>n</em><em> </em><em>is</em><em> </em><em> </em><em>positive</em><em> </em><em>integer</em><em> </em><em>and</em><em> </em><em>the</em><em> </em><em>coefficients</em><em> </em><em>a0</em><em>,</em><em>a1</em><em>,</em><em>A2,</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>an</em><em> </em><em>are</em><em> </em><em>constants</em><em> </em><em>with</em><em> </em><em>an</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>equal</em><em> </em><em>to</em><em> </em><em>0</em><em> </em><em>is</em><em> </em><em>called </em><em>a</em><em> </em><em>poly</em><em>nomial</em><em> </em><em>of</em><em> </em><em>degree</em><em>.</em>

<em>A</em><em> </em><em>poly</em><em>nomial</em><em> </em><em>in</em><em> </em><em>X </em><em>is</em><em> </em><em>denoted </em><em>by</em><em> </em><em>p</em><em>(</em><em>x</em><em>)</em><em>,</em><em>q</em><em>(</em><em>x</em><em>)</em><em>,</em><em>g</em><em>(</em><em>x</em><em>)</em><em> </em><em>etc</em><em>.</em>

<em>Examples</em><em>:</em>

<em>p</em><em>(</em><em>X)</em><em>=</em><em>x^</em><em>2</em><em>-</em><em>3</em><em>x</em><em>+</em><em>2</em><em> </em><em>is</em><em> </em><em>a</em><em> </em><em>polynomial</em><em> </em><em>in </em><em>X.</em>

<em>Similarly</em><em>,</em><em>the</em><em> </em><em>polynomial</em><em> </em><em>in</em><em> </em><em>two </em><em>var</em><em>iables</em><em> </em><em>X </em><em>and</em><em> </em><em>y</em><em> </em><em>are</em><em> </em><em>genera</em><em>lly</em><em> </em><em>denoted</em><em> </em><em>by</em><em> </em><em>p</em><em>(</em><em>x</em><em>,</em><em>y</em><em>)</em><em> </em><em>and</em><em> </em><em>polynomial</em><em> </em><em>in</em><em> </em><em>three</em><em> </em><em>variables</em><em> </em><em>is</em><em> </em><em>denoted</em><em> </em><em>by</em><em> </em><em>p</em><em>(</em><em>x</em><em>,</em><em>y</em><em>,</em><em>z</em><em>)</em><em>.</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em><em>.</em>

Veseljchak [2.6K]3 years ago
6 0

Answer:

A Polynomial can be expressed in terms that only have positive integer exponents and the operations of addition, subtraction, and multiplication. In other words, it must be possible to write the expression without division.

Step-by-step explanation:

<em>EXAMPLES :</em>

  • <em> x2 + 2x +5 Since all of the variables have integer exponents that are positive this is a polynomial.</em>
  • <em>5x +1 Since all of the variables have integer exponents that are positive this is a polynomial.</em>
  • <em>(x7 + 2x4 - 5) * 3x Since all of the variables have integer exponents that are positive this is a polynomial.</em>
  • <em>5x-2 +1 Not a polynomial because a term has a negative exponent</em>
  • <em>3x½ +2 Not a polynomial because a term has a fraction exponent</em>
  • <em>(5x +1) ÷ (3x) Not a polynomial because of the division</em>
  • <em>(6x2 +3x) ÷ (3x) Is actually a polynomial because it's possible to simplify this to 3x + 1 --which of course satisfies the requirements of a polynomial. (Remember the definition states that the expression 'can' be expressed using addition,subtraction, multiplication. So, if it's possible to simplify an expression into a form that uses only those operations and whose exponents are all positive integers...then you do indeed have a polynomial equation) </em>
<h3><em>[Polynomial Equation- is simply a polynomial that has been set equal to]</em></h3>
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seropon [69]

Answer:

The solution set is (-20/9, -95/9)

Step-by-step explanation:

To solve using the substitution method, start by solving the second equation for y.

1/3y = 7/3x + 5/3

y = 7x + 5

Now that we have this, we can plug it in for y in the first equation. Then we can solve for x.

-4x - 2(7x + 5) = 30

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-18x - 10 = 30

-18x = 40

x = -20/9

Now that we have the value of x, we can solve for y by inputting the x value into either equation.

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pav-90 [236]

Answer:

As described in picture:

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Answer:

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Step-by-step explanation:

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