<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em>⤴</em>
<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
Answer:
Step-by-step explanation:
Use the distributive property.
<h3>
What is a distributive property?</h3>
Distributive property is a serving to distribute or allot or disperse.
<u>Distributive property:</u>
A(B+C)=AB+AC
A(B-C)=AB-AC
-10(1-9x)+6(x-10)
<u>Expand.</u>
-10(1-9x)
-10*1=-10
-10*9x=90x

6(x-10)
6*x=6x
6*10=60
6x-60
<u>Rewrite the problem down.</u>
= -10+90x+6x-60
<u>Combine like terms.</u>
90x+6x-10-60
<u>Add the numbers from left to right.</u>
90x+6x=96x
96x-10-60
<u>Finally, subtract the numbers from left to right.</u>
-10-60=-70

Therefore, the final answer is<u> 96x-70.</u>
I hope this helps, let me know if you have any questions.
To learn more about distributive property:
brainly.com/question/2807928
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The quadrants in which all the coordinates given are located is; As explained below.
<h3>How to Identify Quadrants in coordinates?</h3>
1) (2, 4) is located in Quadrant I where both x and y-values are positive.
2) (0, -3) is located in Quadrant II where x - values are positive but y-values are negative.
3) (-1, 1/2) is located in Quadrant IV.
4) (-2 1/2, -7) is located in Quadrant III where x and y values are both negative.
5) (0, 6) is located in Quadrant I where both x and y-values are positive.
6) (-5, 0) is located in Quadrant IV where x is negative but y is positive.
Read more about Quadrant Coordinates at; brainly.com/question/863849
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