let's find the area of the outer circle and the inside circle
the inside's circle area
A= π x 6²=36π
the outer's
A' = π x 4x²= 4πx²
A'-A=4πx²- 36π=160πcm² equivalent to x²- 9=40, so x²=49 implies x =sqrt(49)=7, x=7.
Answer:
Disagreee
Step-by-step explanation:
it has 6 sides so take 360/6 and you'll get 60, so it has to be rotated 60deg for it to be carried onto itself.
10=1+9 1x9=9
=2+8 2x8=16
=3+7 3x7=21
=4+6 4x6=24
=5+5 5x5=25
↑ Left: the possible measurements of the two fences, Right: the possible areas
out of the areas calculated, 25 sq feet is the maximum. :)
Ans: 25 square feet
You uñere línea the niñez Andes circulé the One but
Step-by-step explanation:
Area of Rectangle at the top =
Length x Width

Area of Quarter- Circle = 1/4 x Area of Circle

Area of Rectangle at the right = Length x Width

Total Area = Area of 2 Rectangles + Area of Quarter Circle

I will leave the answer in terms of pi as I'm not sure if you need to round off your answer.