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Luda [366]
4 years ago
12

Which equation has a graph that is a parabola with a vertex at (5,3)?

Mathematics
1 answer:
lara [203]4 years ago
6 0

Answer:

y =  (x -5)² + 3.

Step-by-step explanation:

Given : parabola with a vertex at (5,3).

To find : Which equation has a graph that is a parabola.

Solution : We have given vertex at (5,3).

Vertex form of parabola : y = (x -h)² + k .

Where, (h ,k )  vertex .

Plug h = 5  , k= 3 in vertex form of parabola.

Equation  :y =  (x -5)² + 3.

Therefore, y =  (x -5)² + 3.

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Step-by-step explanation:

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The vertices of Quadrilateral ABCD are located at (1, 4), (5, 0), (2, –3), and (–2, –2).
forsale [732]

Answer:

A - Rectangle B - Square

C - Parallelogram D - Rhombus

Explanation:

We are given

A

(

1

,

2

)

,

B

(

2

,

−

2

)

and hence

A

B

=

√

(

2

−

1

)

2

+

(

−

2

−

2

)

2

=

√

17

. Further slope of

A

B

is

−

2

−

2

2

−

1

=

−

4

1

=

−

4

.

Case A -

C

(

−

6

,

−

4

)

,

D

(

−

7

,

0

)

As

C

D

=

√

(

−

7

−

(

−

6

)

)

2

+

(

0

−

(

−

4

)

)

2

=

√

17

and slope of

C

D

is

0

−

(

−

4

)

−

7

−

(

−

6

)

=

4

−

1

=

−

4

As

A

B

=

C

D

and

A

B

||

C

D

slopes being equal, ABCD is a parallelogram.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x+6)^2+(y+4)^2-0.08)((x+7)^2+y^2-0.08)=0 [-10, 10, -5, 5]}

Case B -

C

(

6

,

−

1

)

,

D

(

5

,

3

)

As

C

D

=

√

(

5

−

6

)

2

+

(

3

−

(

−

1

)

)

2

=

√

17

and slope of

C

D

is

0

−

(

−

4

)

−

7

−

(

−

6

)

=

4

−

1

=

−

4

Further,

B

C

=

√

(

6

−

2

)

2

+

(

−

1

−

(

−

2

)

)

2

=

√

17

and slope of

B

C

is

−

1

−

(

−

2

)

6

−

2

=

1

4

As

B

C

=

A

B

and they are perpendicular (as product of slopes is

−

1

), ABCD is a square.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x-6)^2+(y+1)^2-0.08)((x-5)^2+(y-3)^2-0.08)=0 [-10, 10, -5, 5]}

Case C -

C

(

−

1

,

−

4

)

,

D

(

−

2

,

0

)

As mid point of

A

C

is

(

1

−

1

2

,

2

−

4

2

)

i.e.

(

0

,

−

1

)

and midpoint of

B

D

is

(

2

−

2

2

,

−

2

+

0

2

i.e.

(

0

,

−

1

)

i.e. midpoints of

A

C

and

B

D

are same,

but,

B

C

=

√

(

2

−

(

−

1

)

)

2

+

(

−

2

−

(

−

4

)

)

2

=

√

13

i.e.

A

B

≠

B

C

and hence ABCD is a parallelogram.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x+1)^2+(y+4)^2-0.08)((x+2)^2+y^2-0.08)=0 [-10, 10, -5, 5]}

Case D -

C

(

1

,

−

6

)

,

D

(

0

,

−

2

)

As mid point of

A

C

is

(

1

+

1

2

,

2

−

6

2

)

i.e.

(

1

,

−

2

)

and midpoint of

B

D

is

(

2

+

0

2

,

−

2

+

(

−

2

)

2

i.e.

(

1

,

−

2

)

i.e. midpoints of

A

C

and

B

D

are same,

and,

B

C

=

√

(

2

−

1

)

2

+

(

−

2

−

(

−

6

)

)

2

=

√

17

i.e.

A

B

=

B

C

and hence ABCD is a rhombus.

graph{((x-1)^2+(y-2)^2-0.08)((x-2)^2+(y+2)^2-0.08)((x-1)^2+(y+6)^2-0.08)(x^2+(y+2)^2-0.08)=0 [-14, 14, -7, 7]}

3 0
3 years ago
Find the percent of decrease from 42 to 35. Round to the nearest tenth of a percent if necessary.
Viktor [21]

Answer:

it's 16.67% or 16.7%

Step-by-step explanation:

8 0
3 years ago
The lateral surface area of a cube is 324 cm ² . Find its volume and total surface area​​
AfilCa [17]

Step-by-step explanation:

<h2><u>Given :</u></h2><h2 />
  • Lateral Surface Area of Cube = 324 cm²

\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}}\end{gathered}

<h2><u>To Find :</u></h2>

  • Volume of the Cube = ?

  • Total Surface Area of the Cube = ?

\begin{gathered} \\ {\underline{\rule{200pt}{3pt}}}\end{gathered}

<h2><u>Solution :</u></h2>

<u>~ Formula U</u><u>s</u><u>e</u><u>d</u><u> :</u>

  • Lateral Surface Area :

{\red{\dashrightarrow}} \: \: {\underline{\boxed{\purple{\sf{ Lateral \: Surface \: Area {\small_{(Cube)}} = 4 a² }}}}}

  • Volume :

\large{\red{\dashrightarrow}} \: \: {\underline{\boxed{\purple{\sf{ Volume{\small_{(Cube)}} = a³ }}}}}

  • Total Surface Area :

\large{\red{\dashrightarrow}} \: \: {\underline{\boxed{ \red{\sf{ Total \: Surface \: Area {\small_{(Cube)}} = 6a² }}}}}

\begin{gathered} \\ {\qquad{\rule{150pt}{1pt}}}\end{gathered}

<u>~ Calculating the Side :</u>

\\{\longmapsto{\qquad{\sf{ \cancel\dfrac{324}{4} = a² }}}}

{\longmapsto{\qquad{\sf{ LSA = 4a² }}}}  \\  \\

{\longmapsto{\qquad{\sf{ 324 }}}}

\longmapsto{\qquad{\sf{ 81 = a²}}}

{\longmapsto{\qquad{\sf{ \sqrt{81} = a }}}} \\ \\

{\qquad{\textsf{ Side of the Cube = {\pink{\sf{ 9 \: cm}}}}}}

\begin{gathered} \\ {\qquad{\rule{150pt}{1pt}}}\end{gathered}

<u>~ Calculating the</u><u> </u><u> Volume :</u>

\begin{gathered}{ \red{\longmapsto{\qquad{\sf{ Volume = a³ }}}}} \\ \\ \  { \pink{\longmapsto{\qquad{\sf{ Volume = 9³ }}}} }\\ \\ \ { \green{\longmapsto{\qquad{\sf{ Volume = 9 \times 9 \times 9 }}}}} \\ \\ \ { \purple{\qquad{\textsf{ Volume of the Cube = {\green{\sf{ \boxed{\longmapsto  \sf729 \: cm³ }}}}}}}}\end{gathered}

<u>~ Calculating the</u><u> Total Surface Area :</u>

{\longmapsto{\qquad{\sf{ TSA = 6a² }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ TSA = 6 \times 9² }}}} \\ \\ \ {\longmapsto{\qquad{\sf{ TSA = 6 \times 9 \times 9 }}}}

{\longmapsto{\qquad{\sf{ TSA = 6 \times 81 }}}} \\ \\ \ {\qquad{\textsf{ Total Surface Area of the Cube = {\red{\sf{ 486 \: cm² }}}}}}

<h2><u>Therefore :</u></h2>

  • ❝ Volume of the Cube is 729 cm³ and it's Total Surface Area is 486 cm² .❞

\begin{gathered} \\ {\pink{\underline{\rule{75pt}{9pt}}}}{\blue{\underline{\rule{75pt}{9pt}}}}{\color{cyan}{\underline{\rule{75pt}{9pt}}}}\end{gathered}

5 0
3 years ago
Read 2 more answers
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