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Akimi4 [234]
3 years ago
5

Which figure below has point symmetry

Mathematics
1 answer:
Contact [7]3 years ago
8 0

Answer:

Figure D

Step-by-step explanation:

Point Symmetry is when every part has a matching part: the same distance from the central point. but in the opposite direction. Hope this helps! :)

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Please, I can really use some help. I have no idea how to solve this.
lions [1.4K]
A.
Use technology to plot the graph.
Here it is using wolframalpha.com.
http://www.wolframalpha.com/input/?i=y+%3D+-5;+y+%3D+3x+-+2+for+-2%3C%3Dx%3C%3D2

B.
The solution is where the graphs of the lines intersect. It is at point (-1, -5).

C.
y = -5
y = 3x - 2
-5 = 3x - 2
3x = -3
x = -1
The solution is (-1, -5) which is the same as with the graph.
8 0
3 years ago
Read 2 more answers
Y=3x-5x=32.7+4.1y-6.8-x-y=92x+y=-18y-5=x Determine if they are standard form or not standard form
mote1985 [20]

The standard form of a linear equation is:

Ax+By=C

A and B are integers

C is a constant

Then, of the given equation the next are writen in standard form:

\begin{gathered} -x-y=0 \\  \\ 2x+y=-1 \\  \end{gathered}

4 0
2 years ago
The formula for finding the perimeter of a rectangle is P = 2L + 2W. If a rectangle has a perimeter of 68 inches and the length
Artemon [7]

Answer:

Width = 10 inches

Step-by-step explanation:

Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.

We can establish the following values to help us solve for the width of a rectangle:

Perimeter (P) = 68 inches

Length (L) = 14 + W inches

Width (W) = unknown

<h3 /><h3><u>Solve for the Width (W)</u></h3>

P =  2(L + W)  ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.

Divide both sides by 2:

\displaystyle\mathsf{\frac{P}{2}\:=\:\frac{2(L\:+\:W)}{2}}

\displaystyle\mathsf{\frac{P}{2}\:=L\:+\:W}

Substitute the value of the Perimeter and the length (L) into the formula:

\displaystyle\mathsf{\frac{68}{2}\:=14\:+W\:+\:W}

Combine like terms on the right-hand side, and simplify the left-hand side of the equation:

\displaystyle\mathsf{34\:=14\:+2W}

Subtract 14 from both sides:

34 - 14 = 14 - 14 + 2W

20 = 2W

Divide both sides by 2 to solve for the width (W):

\displaystyle\mathsf{\frac{20}{2}\:=\:\frac{2W}{2}}

W = 10 inches

Therefore, the width of the rectangle is 10 inches.

<h3 /><h3><u>Double-check:</u></h3>

Verify whether the derived value for the width is correct:

P = 2L + 2W

68 = 2(14 + 10) + 2(10)

68 = 2(34) + 20

68 = 48 + 20

68 = 68 (True statement).  

Thus, the length of the rectangle is 34 inches, and the width is 10 inches.

4 0
3 years ago
HELP ME PLZZ!!!!!!!!!!!"
MArishka [77]
I hope you can read cursive writing and I hope this helps! (:

6 0
3 years ago
Can someone solve this please
Elanso [62]
Question 47= 33 ounces
Question 48= 98 Fahrenheit
Question 49= 127 millimeters
Last question= 2 inches
7 0
3 years ago
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